Output of C programs | Set 55 (Shift Operators)
Prerequisite: Shift operators
Q.1 What Is The Output Of this program?
ans :- b
Explanation :- We know that 0x is hexa-decimal representation of number so 80 converted in decimal is 128 binary(10000000), its left shift 1 so it is (100000000)equal to 256.
Q.2 What Is The Output Of this program?
a) 65535 -65536
b) -65535 65535
c) 65535 65535
d) -65535 -65535
ans :- a
Explanation :- This code 0x is Hexadecimal representation of number so ffff hexadecimal is converted into Decimal 65535 and stored in a. The negation of a -65535 is stored in k. k is an unsigned integer but it has a negative value in it. When k is being printed the format specifier is %d which represents signed integer thus -65536 gets printed as value of k. If the format specifier for k had been %u the value that would have been printed is 4294901760.
Q.3 What Is The Output Of this program?
ans :- d
Explanation :- Here a integer is simply left-shifted 4 bit and print so it is -16.
Q.4 What Is The Output Of this program?
a) 16 5
b) 64 -32
c) 16 33
d) 16 -33
ans :- d
Explanation :- This program 32 is(10000) and we know that negative number in binary system contain a one’s complement so here take a complement of a number and only print this number so the negation of 32 is -33.
Q.5 What Is The Output Of this program?
a) -2, 7
b) 2, 8
c) -1, 15
d) -2, 15
ans :- a
Explanation :- Here -1 binary(0001) if left shift 1 so it is -2(0010) and 15 binary(1111) is right shift 1 so it is (0111)so value 7.
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