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numpy.isfortran() in Python
  • Last Updated : 29 Nov, 2018

numpy.isfortran(array) : This is a logical function that checks whether array is Fortran contiguous or not.

Order : [C-contiguous, F-contiguous, A-contiguous; optional]

C-contiguous order in memory(last index varies the fastest). C order means that operating row-rise on the array will be slightly quicker.
FORTRAN-contiguous order in memory (first index varies the fastest). F order means that column-wise operations will be faster.
‘A’ means to read / write the elements in Fortran-like index order if, array is Fortran contiguous in memory, C-like order otherwise.

Parameters :

array    : [array_like]Input array 

Return :



True, if array is Fortran; else False

Code 1 :




# Python program explaining
# isfortran() function
import numpy as np
  
in_array = np.array([[1, 2, 3], [4, 5, 6]], order='C')
print ("Input array : \n", in_array)
  
exp2_values = np.exp2(in_array)
print ("\nisfortran : ", np.isfortran(in_array))


Output :

Input array : 
 [[1 2 3]
 [4 5 6]]

isfortran :  False

 
Code 2 :




# Python program explaining
# isfortran() function
import numpy as np
  
in_array = np.array([[1, 2, 3], [4, 5, 6]], order='F')
print ("Input array : \n", in_array)
  
exp2_values = np.exp2(in_array)
print ("\nisfortran : ", np.isfortran(in_array))


Output :

Input array : 
 [[1 2 3]
 [4 5 6]]

isfortran :  True

References :
https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.isfortran.html#numpy.isfortran
.

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