# Number of ways to select a node from each connected component

Given a graph with **N** nodes and **M** edges. The task is to find the number of ways to select a node from each connected component of the given graph.

**Examples:**

Input:

Output:3

(1, 4), (2, 4), (3, 4) are possible ways.

Input:

Output:6

(1, 4, 5), (2, 4, 5), (3, 4, 5), (1, 4, 6), (2, 4, 6), (3, 4, 6) are possible ways.

**Approach:** A product of the number of nodes in each connected component is the required answer. Run a simple dfs to find the number of nodes in each connected component.

Below is the implementation of the above approach:

## C++

`// C++ implementation of the approach ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` `#define N 100005 ` ` ` `int` `n, m, temp; ` `vector<` `int` `> gr[N]; ` `int` `vis[N]; ` ` ` `// Function to add edges in the graph ` `void` `Add_edges(` `int` `x, ` `int` `y) ` `{ ` ` ` `gr[x].push_back(y); ` ` ` `gr[y].push_back(x); ` `} ` ` ` `// Function for DFS ` `void` `dfs(` `int` `ch) ` `{ ` ` ` `// Mark node as visited ` ` ` `vis[ch] = 1; ` ` ` ` ` `// Count number of nodes in a component ` ` ` `temp++; ` ` ` `for` `(` `auto` `i : gr[ch]) ` ` ` `if` `(!vis[i]) ` ` ` `dfs(i); ` `} ` ` ` `// Function to return the required number of ways ` `int` `NumberOfWays() ` `{ ` ` ` ` ` `// To store the required answer ` ` ` `int` `ans = 1; ` ` ` ` ` `memset` `(vis, 0, ` `sizeof` `vis); ` ` ` `for` `(` `int` `i = 1; i <= n; i++) { ` ` ` ` ` `// If current node hasn't been visited yet ` ` ` `if` `(!vis[i]) { ` ` ` `temp = 0; ` ` ` `dfs(i); ` ` ` ` ` `// Multiply it with the answer ` ` ` `ans *= temp; ` ` ` `} ` ` ` `} ` ` ` ` ` `return` `ans; ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `n = 4, m = 2; ` ` ` ` ` `// Add edges ` ` ` `Add_edges(1, 2); ` ` ` `Add_edges(1, 3); ` ` ` ` ` `cout << NumberOfWays(); ` ` ` ` ` `return` `0; ` `} ` |

*chevron_right*

*filter_none*

## Python3

# Python3 implementation of the approach

# Function to add edges in the graph

def Add_edges(x, y):

gr[x].append(y)

gr[y].append(x)

# Function for DFS

def dfs(ch):

# Mark node as visited

vis[ch] = 1

global temp

# Count number of nodes

# in a component

temp += 1

for i in gr[ch]:

if not vis[i]:

dfs(i)

# Function to return the required

# number of ways

def NumberOfWays():

# To store the required answer

ans = 1

global temp

for i in range(1, n + 1):

# If current node hasn’t been

# visited yet

if not vis[i]:

temp = 0

dfs(i)

# Multiply it with the answer

ans *= temp

return ans

# Driver code

if __name__ == “__main__”:

n, m, temp = 4, 2, 0

N = 100005

gr = [[] for i in range(N)]

vis = [None] * N

# Add edges

Add_edges(1, 2)

Add_edges(1, 3)

print(NumberOfWays())

# This code is contributed by Rituraj Jain

**Output:**

3

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