Given an integer N, the task is to find the minimum possible integer X such that X % M = 1 for all M from the range [2, N]
Input: N = 5
61 % 2 = 1
61 % 3 = 1
61 % 4 = 1
61 % 5 = 1
Input: N = 2
Approach: Find the lcm of all the integers from the range [2, N] and store it in a variable lcm. Now we know that lcm is the smallest number which is divisible by all the elements from the range [2, N] and to make it leave a remainder of 1 on every division, just add 1 to it i.e. lcm + 1 is the required answer.
Below is the implementation of the above approach:
- Largest number by which given 3 numbers should be divided such that they leaves same remainder
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- Smallest number dividing minimum number of elements in the Array
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- Maximum positive integer divisible by C and is in the range [A, B]
- Find an integer in the given range that satisfies the given conditions
- Biggest integer which has maximum digit sum in range from 1 to n
- Find an integer X which is divisor of all except exactly one element in an array
- Smallest integer > 1 which divides every element of the given array
- Sum of (maximum element - minimum element) for all the subsets of an array.
- Minimum positive integer value possible of X for given A and B in X = P*A + Q*B
- Minimum numbers needed to express every integer below N as a sum
- Minimum positive integer to divide a number such that the result is an odd
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