Matplotlib.pyplot.gci() in Python

Matplotlib is a library in Python and it is numerical – mathematical extension for NumPy library. Pyplot is a state-based interface to a Matplotlib module which provides a MATLAB-like interface. There are various plots which can be used in Pyplot are Line Plot, Contour, Histogram, Scatter, 3D Plot, etc.

matplotlib.pyplot.gci() method

The gci() method in pyplot module of matplotlib library is used to get the current colorable artist.

Syntax: matplotlib.pyplot.gci()

Parameters: This method does not accept any parameters.

Returns: This method returns the current colorable artist.

Below examples illustrate the matplotlib.pyplot.gci() function in matplotlib.pyplot:

Example 1:

# Implementation of matplotlib function
import matplotlib.pyplot as plt
import numpy as np
import matplotlib.gridspec as gridspec
from mpl_toolkits.axes_grid1 import make_axes_locatable


plt.close('all')
arr = np.arange(100).reshape((10, 10))
fig = plt.figure(figsize =(4, 4))
im = plt.imshow(arr,
                interpolation ="none",
                cmap ="plasma")

divider = make_axes_locatable(plt.gca())
cax = divider.append_axes("left",
                          "15 %",
                          pad ="30 %")

plt.colorbar(im, cax = cax)

print("The current colorable artist is :")
print(plt.gci())

fig.suptitle('matplotlib.pyplot.gci() function \
Example\n\n', fontweight ="bold")

plt.show()

Output:

The current colorable artist is :
AxesImage(50, 44;310x308)

Example 2:

# Implementation of matplotlib function
import matplotlib.pyplot as plt
from scipy import sin, cos


fig, ax = plt.subplots(2, 1)
x = [1, 2, 3, 4, 5, 6, 7, 8, 9]

y1 = sin(x)
y2 = cos(x)

plt.sca(ax[0])
plt.plot(x, y1)

plt.sca(ax[1])
plt.plot(x, y2)

print("The current colorable artist is :")
print(plt.gci())

fig.suptitle('matplotlib.pyplot.gci() function \
Example\n\n', fontweight ="bold")

plt.show()

Output:

The current colorable artist is :
None