# Left rotation of an array using vectors in C++

Given an array arr[] of integers and another integer D, the task is to perform D left rotations on the array and print the modified array.

Examples:

```Input: arr[] = {1, 2, 3, 4, 5, 6}, D = 2
Output: 3 4 5 6 1 2

Input: arr[] = {1, 2, 3, 4, 5, 6}, D = 12
Output: 1 2 3 4 5 6
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: Using vectors in C++, a rotation can be performed by removing the first element from the vector and then inserting it in the end of the same vector. Similarly, all the requried rotations can be performed and then print the contents of the modified vector to get the required rotated array.

Below is the implementation of the above approach:

 `// C++ implementation of the approach ` `#include ` `using` `namespace` `std; ` ` `  `// Function to left rotate the array by d elements ` `void` `rotate(vector<``int``> vec, ``int` `d) ` `{ ` ` `  `    ``// Push first d elements from the beginning ` `    ``// to the end and remove those elements ` `    ``// from the beginning ` `    ``for` `(``int` `i = 0; i < d; i++) { ` `        ``vec.push_back(vec); ` `        ``vec.erase(vec.begin()); ` `    ``} ` ` `  `    ``// Print the rotated array ` `    ``for` `(``int` `i = 0; i < vec.size(); i++) { ` `        ``cout << vec[i] << ``" "``; ` `    ``} ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``vector<``int``> vec = { 1, 2, 3, 4, 5, 6 }; ` `    ``int` `n = vec.size(); ` `    ``int` `d = 2; ` ` `  `    ``rotate(vec, d % n); ` ` `  `    ``return` `0; ` `} `

Output:

```3 4 5 6 1 2
```

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