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kth smallest/largest in a small range unsorted array

  • Difficulty Level : Easy
  • Last Updated : 11 May, 2021

Find kth smallest or largest element in an unsorted array, where k<=size of array. It is given that elements of array are in small range.
Examples: 
 

Input : arr[] = {3, 2, 9, 5, 7, 11, 13}
        k = 5
Output: 9

Input : arr[] = {16, 8, 9, 21, 43}
        k = 3
Output: 16

Input : arr[] = {50, 50, 40}
        k = 2
Output: 50

 

As the given array elements are in small range, we can direct index table to do something similar to counting sort. We store counts of elements, then we traverse the count array and print k-th element.
Following is the implementation of the above algorithm
 

C++




// C++ program of kth smallest/largest in
// a small range unsorted array
#include <bits/stdc++.h>
using namespace std;
#define maxs 1000001
 
int kthSmallestLargest(int* arr, int n, int k)
{
    int max_val = *max_element(arr, arr+n);
    int hash[max_val+1] = { 0 };
 
    // Storing counts of elements
    for (int i = 0; i < n; i++)
        hash[arr[i]]++;   
     
    // Traverse hash array build above until
    // we reach k-th smallest element.
    int count = 0;
    for (int i=0; i <= max_val; i++)
    {
        while (hash[i] > 0)
        {
           count++;
           if (count == k)
              return i;
           hash[i]--;
        }
    }
     
    return -1;
}
 
int main()
{
    int arr[] = { 11, 6, 2, 9, 4, 3, 16 };
    int n = sizeof(arr) / sizeof(arr[0]), k = 3;
    cout << "kth smallest number is: "
         << kthSmallestLargest(arr, n, k) << endl;
    return 0;
}

Java




// Java program of kth smallest/largest in
// a small range unsorted array
import java.util.Arrays;
 
class GFG
{
 
    static int maxs = 1000001;
 
    static int kthSmallestLargest(int[] arr, int n, int k)
    {
        int max_val = Arrays.stream(arr).max().getAsInt();
        int hash[] = new int[max_val + 1];
 
        // Storing counts of elements
        for (int i = 0; i < n; i++)
        {
            hash[arr[i]]++;
        }
 
        // Traverse hash array build above until
        // we reach k-th smallest element.
        int count = 0;
        for (int i = 0; i <= max_val; i++)
        {
            while (hash[i] > 0)
            {
                count++;
                if (count == k)
                {
                    return i;
                }
                hash[i]--;
            }
        }
 
        return -1;
    }
 
    // Driver code
    public static void main(String[] args)
    {
        int arr[] = {11, 6, 2, 9, 4, 3, 16};
        int n = arr.length, k = 3;
        System.out.println("kth smallest number is: "
                + kthSmallestLargest(arr, n, k));
    }
}
 
// This code has been contributed by 29AjayKumar

Python3




# Python 3 program of kth smallest/largest
# in a small range unsorted array
 
def kthSmallestLargest(arr, n, k):
    max_val = arr[0]
    for i in range(len(arr)):
        if (arr[i] > max_val):
            max_val = arr[i]
    hash = [0 for i in range(max_val + 1)]
 
    # Storing counts of elements
    for i in range(n):
        hash[arr[i]] += 1
     
    # Traverse hash array build above until
    # we reach k-th smallest element.
    count = 0
    for i in range(max_val + 1):
        while (hash[i] > 0):
            count += 1
            if (count == k):
                return i
            hash[i] -= 1
         
    return -1
 
# Driver Code
if __name__ == '__main__':
    arr = [11, 6, 2, 9, 4, 3, 16]
    n = len(arr)
    k = 3
    print("kth smallest number is:",
           kthSmallestLargest(arr, n, k))
     
# This code is contributed by
# Surendra_Gangwar

C#




// C# program of kth smallest/largest in
// a small range unsorted array
using System;
using System.Linq;
 
class GFG
{
 
    static int maxs = 1000001;
 
    static int kthSmallestLargest(int[] arr, int n, int k)
    {
        int max_val = arr.Max();
        int []hash = new int[max_val + 1];
 
        // Storing counts of elements
        for (int i = 0; i < n; i++)
        {
            hash[arr[i]]++;
        }
 
        // Traverse hash array build above until
        // we reach k-th smallest element.
        int count = 0;
        for (int i = 0; i <= max_val; i++)
        {
            while (hash[i] > 0)
            {
                count++;
                if (count == k)
                {
                    return i;
                }
                hash[i]--;
            }
        }
        return -1;
    }
 
    // Driver code
    public static void Main()
    {
        int []arr = {11, 6, 2, 9, 4, 3, 16};
        int n = arr.Length, k = 3;
        Console.WriteLine("kth smallest number is: "
                + kthSmallestLargest(arr, n, k));
    }
}
 
/* This code contributed by PrinciRaj1992 */

PHP




<?php
// PHP program of kth smallest/largest in
// a small range unsorted array
$maxs = 1000001;
  
function kthSmallestLargest(&$arr, $n, $k)
{
    global $maxs;
    $max_val = max($arr);
    $hash = array_fill(0,$max_val+1, NULL);
  
    // Storing counts of elements
    for ($i = 0; $i < $n; $i++)
        $hash[$arr[$i]]++;   
      
    // Traverse hash array build above until
    // we reach k-th smallest element.
    $count = 0;
    for ($i=0; $i <= $max_val; $i++)
    {
        while ($hash[$i] > 0)
        {
           $count++;
           if ($count == $k)
              return $i;
           $hash[$i]--;
        }
    }
      
    return -1;
}
  
 
    $arr = array ( 11, 6, 2, 9, 4, 3, 16 );
    $n = sizeof($arr) / sizeof($arr[0]);
    $k = 3;
    echo "kth smallest number is: "
         . kthSmallestLargest($arr, $n, $k)."\n";
    return 0;
?>

Javascript




<script>
// Javascript program of kth smallest/largest in
// a small range unsorted array
     
    let maxs = 1000001;
    function kthSmallestLargest(arr,n,k)
    {
        let max_val = Math.max(...arr);
        let hash = new Array(max_val + 1);
        for(let i=0;i<hash.length;i++)
        {
            hash[i]=0;
        }
   
        // Storing counts of elements
        for (let i = 0; i < n; i++)
        {
            hash[arr[i]]++;
        }
   
        // Traverse hash array build above until
        // we reach k-th smallest element.
        let count = 0;
        for (let i = 0; i <= max_val; i++)
        {
            while (hash[i] > 0)
            {
                count++;
                if (count == k)
                {
                    return i;
                }
                hash[i]--;
            }
        }
   
        return -1;
    }
     
    // Driver code
    let arr=[11, 6, 2, 9, 4, 3, 16];
    let n = arr.length, k = 3;
    document.write("kth smallest number is: "
                + kthSmallestLargest(arr, n, k));
     
 
// This code is contributed by avanitrachhadiya2155
</script>
Output: 
kth smallest number is: 4

 

Time Complexity: O(n + max_val)
 

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