Form coils in a matrix

Given a positive integer n that represents dimensions of a 4n x 4n matrix with values from 1 to n filled from left to right and top to bottom. Form two coils from matrix and print the coils.

Examples:

Input  : n = 1;
Output : Coil 1 : 10 6 2 3 4 8 12 16
Coil 2 : 7 11 15 14 13 9 5 1
Explanation : Matrix is
1  2  3  4
5  6  7  8
9  10 11 12
13 14 15 16

Input  : n = 2;
Output : Coil 1 : 36 28 20 21 22 30 38 46 54
53 52 51 50 42 34 26 18 10
2 3 4 5 6 7 8 16 24 32 40
48 56 64
Coil 2 : 29 37 45 44 43 35 27 19 11 12
13 14 15 23 31 39 47 55 63 62
61 60 59 58 57 49 41 33 25 17
9 1 Recommended: Please solve it on “PRACTICE” first, before moving on to the solution.

Total elements in matrix are 16n2. All elements are divided in two coils. Every coil has 8n2 elements. We make two arrays of this size. We first fill elements in coil1 by traversing in given order. Once we have filled elements in coil1, we can get elements of other coil2 using formula coil2[i] = 16*n*n + 1 -coil1[i].

C++

 // C++ program to print 2 coils of a // 4n x 4n matrix. #include using namespace std;    // Print coils in a matrix of size 4n x 4n  void printCoils(int n) {     // Number of elements in each coil     int m = 8*n*n;        // Let us fill elements in coil 1.     int coil1[m];        // First element of coil1     // 4*n*2*n + 2*n;     coil1 = 8*n*n + 2*n;     int curr = coil1;        int nflg = 1, step = 2;        // Fill remaining m-1 elements in coil1[]     int index = 1;     while (index < m)     {         // Fill elements of current step from         // down to up         for (int i=0; i= m)                 break;         }         if (index >= m)             break;            // Fill elements of current step from         // up to down.         for (int i=0; i= m)                 break;         }         nflg = nflg*(-1);         step += 2;     }        /* get coil2 from coil1 */     int coil2[m];     for (int i=0; i<8*n*n; i++)         coil2[i] = 16*n*n + 1 -coil1[i];        // Print both coils     cout << "Coil 1 : ";     for(int i=0; i<8*n*n; i++)         cout << coil1[i] << " ";     cout << "\nCoil 2 : ";     for (int i=0; i<8*n*n; i++)         cout << coil2[i] << " "; }    // Driver code int main() {     int n = 1;     printCoils(n);     return 0; }

Java

 // Java program to print 2 coils  // of a 4n x 4n matrix.    class GFG {            // Print coils in a matrix of size 4n x 4n     static void printCoils(int n)      {         // Number of elements in each coil         int m = 8 * n * n;                // Let us fill elements in coil 1.         int coil1[] = new int[m];                // First element of coil1         // 4*n*2*n + 2*n;         coil1 = 8 * n * n + 2 * n;         int curr = coil1;                int nflg = 1, step = 2;                // Fill remaining m-1 elements in coil1[]         int index = 1;         while (index < m)         {             // Fill elements of current step from             // down to up             for (int i = 0; i < step; i++)                  {                     // Next element from current element                     curr = coil1[index++] = (curr - 4 * n * nflg);                     if (index >= m)                     break;                 }             if (index >= m)                 break;                        // Fill elements of current step from             // up to down.             for (int i = 0; i < step; i++)              {                 curr = coil1[index++] = curr + nflg;                 if (index >= m)                 break;             }                            nflg = nflg * (-1);             step += 2;         }                /* get coil2 from coil1 */         int coil2[] = new int[m];         for (int i = 0; i < 8 * n * n; i++)             coil2[i] = 16 * n * n + 1 - coil1[i];                // Print both coils         System.out.print("Coil 1 : ");                    for (int i = 0; i < 8 * n * n; i++)             System.out.print(coil1[i] + " ");                    System.out.print("\nCoil 2 : ");                    for (int i = 0; i < 8 * n * n; i++)             System.out.print(coil2[i] + " ");     }            // Driver code     public static void main(String[] args)     {         int n = 1;         printCoils(n);     } }    // This code is contributed by Anant Agarwal.

C#

 // C# program to print 2 coils  // of a 4n x 4n matrix. using System;    class GFG {            // Print coils in a matrix of     // size 4n x 4n     static void printCoils(int n)      {                    // Number of elements in         // each coil         int m = 8 * n * n;                // Let us fill elements in         // coil 1.         int [] coil1 = new int[m];                // First element of coil1         // 4*n*2*n + 2*n;         coil1 = 8 * n * n + 2 * n;         int curr = coil1;                int nflg = 1, step = 2;                // Fill remaining m-1 elements         // in coil1[]         int index = 1;         while (index < m)         {                            // Fill elements of current             // step from down to up             for (int i = 0; i < step; i++)                  {                     // Next element from                      // current element                     curr = coil1[index++]                      = (curr - 4 * n * nflg);                                            if (index >= m)                         break;                 }                                if (index >= m)                 break;                        // Fill elements of current step             // from up to down.             for (int i = 0; i < step; i++)              {                 curr = coil1[index++] = curr                                       + nflg;                 if (index >= m)                     break;             }                            nflg = nflg * (-1);             step += 2;         }                /* get coil2 from coil1 */         int [] coil2 = new int[m];                    for (int i = 0; i < 8 * n * n; i++)             coil2[i] = 16 * n * n + 1 - coil1[i];                // Print both coils         Console.Write("Coil 1 : ");                    for (int i = 0; i < 8 * n * n; i++)             Console.Write(coil1[i] + " ");                    Console.Write("\nCoil 2 : ");                    for (int i = 0; i < 8 * n * n; i++)             Console.Write(coil2[i] + " ");     }            // Driver code     public static void Main()     {         int n = 1;                    printCoils(n);     } }    // This code is contributed by KRV.

PHP

 = \$m)                 break;         }         if (\$index >= \$m)             break;            // Fill elements of current step from         // up to down.         for ( \$i=0; \$i<\$step; \$i++)         {             \$curr = \$coil1[\$index++] =                              \$curr + \$nflg;             if (\$index >= \$m)                 break;         }         \$nflg = \$nflg * (-1);         \$step += 2;     }        /* get coil2 from coil1 */     \$coil2 = array();            for ( \$i = 0; \$i < 8 * \$n * \$n; \$i++)         \$coil2[\$i] = 16 * \$n * \$n + 1 -\$coil1[\$i];        // Print both coils     echo "Coil 1 : ";     for( \$i = 0; \$i < 8 * \$n * \$n; \$i++)     echo \$coil1[\$i] , " ";            echo "\nCoil 2 : ";     for ( \$i = 0; \$i < 8 * \$n * \$n; \$i++)         echo \$coil2[\$i] , " "; }    // Driver code \$n = 1; printCoils(\$n);    // This code is contributed by anuj_67. ?>

Output:

Coil 1 : 10 6 2 3 4 8 12 16
Coil 2 : 7 11 15 14 13 9 5 1

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Improved By : KRV, vt_m

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