Related Articles
Find the XOR of first half and second half elements of an array
• Last Updated : 22 Apr, 2021

Given an array arr of size N. The task is to find the XOR of the first half (N/2) elements and second half elements (N – N/2) of an array.
Examples:

Input: arr[]={20, 30, 50, 10, 55, 15, 42}
Output: 56, 24
Explanation:
XOR of first half elements 20 ^ 30 ^ 50 is 56
Xor of second half elements 10 ^ 55 ^ 15 ^ 42 is 24
Input: arr[]={50, 45, 36, 6, 8, 87}
Output: 59, 89

Approach:

1. Initialize FirstHalfXOR and SecondHalfXOR as 0.

2. Traverse the array and XOR elements in FirstHalfXOR until the current index is less than N/2.

3. Otherwise, XOR elements in SecondHalfXOR.

Below is the implementation of the above approach:

## C++

 `// C++ program to find the xor of``// the first half elements and``// second half elements of an array``#include ``using` `namespace` `std;` `// Function to find the xor of``// the first half elements and``// second half elements of an array``void` `XOROfElements(``int` `arr[], ``int` `n){` `    ``int` `FirstHalfXOR = 0;``    ``int` `SecondHalfXOR = 0;` `    ``for``(``int` `i=0; i < n; i++){``        ` `        ``// xor of elements in FirstHalfXOR``        ``if` `(i < n / 2)``            ``FirstHalfXOR ^= arr[i];` `        ``// xor of elements in SecondHalfXOR``        ``else``            ``SecondHalfXOR ^= arr[i];``    ``}   ``    ``cout << FirstHalfXOR << ``","` `<< SecondHalfXOR << endl;` `}` `// Driver Code``int` `main() {``    ``int` `arr[] = {20, 30, 50, 10, 55, 15, 42};` `    ``int` `N = ``sizeof``(arr)/``sizeof``(arr[0]);` `    ``// Function call``    ``XOROfElements(arr, N);``    ` `    ``return` `0;``}` `// This code is contributed by AnkitRai01`

## Java

 `// Java program to find the xor of``// the first half elements and``// second half elements of an array` `class` `GFG{` `// Function to find the xor of``// the first half elements and``// second half elements of an array``static` `void` `XOROfElements(``int` `arr[], ``int` `n){` `    ``int` `FirstHalfXOR = ``0``;``    ``int` `SecondHalfXOR = ``0``;` `    ``for``(``int` `i = ``0``; i < n; i++){``        ` `        ``// xor of elements in FirstHalfXOR``        ``if` `(i < n / ``2``)``            ``FirstHalfXOR ^= arr[i];` `        ``// xor of elements in SecondHalfXOR``        ``else``            ``SecondHalfXOR ^= arr[i];``    ``}``    ``System.out.print(FirstHalfXOR + ``","``                     ``+ SecondHalfXOR + ``"\n"``);` `}` `// Driver Code``public` `static` `void` `main(String[] args)``{``    ``int` `arr[] = { ``20``, ``30``, ``50``, ``10``, ``55``, ``15``, ``42` `};` `    ``int` `N = arr.length;` `    ``// Function call``    ``XOROfElements(arr, N);``    ` `}``}` `// This code is contributed by 29AjayKumar`

## Python3

 `# Python3 program to find the xor of``# the first half elements and``# second half elements of an array` `# Function to find the xor of``# the first half elements and``# second half elements of an array``def` `XOROfElements(arr, n):` `    ``FirstHalfXOR ``=` `0``;``    ``SecondHalfXOR ``=` `0``;` `    ``for` `i ``in` `range``(n):``        ` `        ``# xor of elements in FirstHalfXOR``        ``if` `(i < n ``/``/` `2``):``            ``FirstHalfXOR ^``=` `arr[i];` `        ``# xor of elements in SecondHalfXOR``        ``else``:``            ``SecondHalfXOR  ^``=` `arr[i];``            ` `    ``print``(FirstHalfXOR,``","``,SecondHalfXOR);` `# Driver Code``arr ``=` `[``20``, ``30``, ``50``, ``10``, ``55``, ``15``, ``42``];` `N ``=` `len``(arr);` `# Function call``XOROfElements(arr, N);`

## C#

 `// C# program to find the xor of``// the first half elements and``// second half elements of an array``using` `System;` `class` `GFG{` `// Function to find the xor of``// the first half elements and``// second half elements of an array``static` `void` `XOROfElements(``int` `[]arr, ``int` `n)``{``    ``int` `FirstHalfXOR = 0;``    ``int` `SecondHalfXOR = 0;` `    ``for``(``int` `i = 0; i < n; i++)``    ``{``       ` `       ``// xor of elements in FirstHalfXOR``       ``if` `(i < n / 2)``           ``FirstHalfXOR ^= arr[i];``           ` `       ``// xor of elements in SecondHalfXOR``       ``else``           ``SecondHalfXOR ^= arr[i];``    ``}``    ` `    ``Console.Write(FirstHalfXOR + ``","` `+``                  ``SecondHalfXOR + ``"\n"``);``}` `// Driver Code``public` `static` `void` `Main(String[] args)``{``    ``int` `[]arr = { 20, 30, 50, 10, 55, 15, 42 };``    ``int` `N = arr.Length;` `    ``// Function call``    ``XOROfElements(arr, N);``}``}` `// This code is contributed by 29AjayKumar`

## Javascript

 ``
Output:
`56, 24`

Time complexity: O(N)

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.  To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.

In case you wish to attend live classes with industry experts, please refer Geeks Classes Live and Geeks Classes Live USA

My Personal Notes arrow_drop_up