Find the slope of the given number num. Slope of a number is the count of the minima and maxima digits in it. A digit is called a minima if the digit is lesser than the digit before and after it. Similarly a digit is called a maxima if the digit is greater than the digit before and after it.
Input : 1213321 Output : 2 1213321- The highlighted digit '2' is a maxima and highlighted digit '1' is a minima. Input : 273299302236131 Output : 6
Approach: Traverse the digits of the given number from the 2nd digit up to the 2nd last digit. For each digit check whether the digit is greater or smaller than digits before and after it. Get the count of such digits.
# Python 3 implementation to find
# slope of a number
# function to find slope of a number
def slopeOfNum(num, n):
# to store slope of the given
# number ‘num’
slope = 0
# loop from the 2nd digit up
# to the 2nd last digit
# of the given number ‘num’
for i in range(1, n – 1) :
# if the digit is a maxima
if (num[i] > num[i – 1] and
num[i] > num[i + 1]):
slope += 1
# if the digit is a minima
elif (num[i] < num[i - 1] and num[i] < num[i + 1]): slope += 1 # required slope return slope # Driver Code if __name__ == "__main__": num = "1213321" n = len(num) print("Slpoe =", slopeOfNum(num, n)) # This code is contributed by ita_c [tabby title="C#"]
Slope = 2
Time complexity: O(n).
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