# Program to find slope of a line

Given two coordinates, find the slope of a straight line.

Examples:

```Input  : x1 = 4, y1 = 2,
x2 = 2, y2 = 5
Output : Slope is -1.5```

Approach: To calculate the slope of a line you need only two points from that line, (x1, y1) and (x2, y2). The equation used to calculate the slope from two points is:

Below is the implementation of the above approach:

## C++

 `// C++ program for slope of line ` `#include ` `using` `namespace` `std; ` ` `  `// function to find the slope of a straight line ` `float` `slope(``float` `x1, ``float` `y1, ``float` `x2, ``float` `y2) ` `{ ` `    ``if` `(x2 - x1 != 0) ` `        ``return` `(y2 - y1) / (x2 - x1); ` `    ``return` `INT_MAX; ` `} ` ` `  `// driver code to check the above function ` `int` `main() ` `{ ` `    ``float` `x1 = 4, y1 = 2; ` `    ``float` `x2 = 2, y2 = 5; ` `    ``cout << ``"Slope is: "` `<< slope(x1, y1, x2, y2); ` `    ``return` `0; ` `}`

## Java

 `// Java program for slope of line ` `import` `java.io.*; ` ` `  `class` `GFG { ` `    ``static` `float` `slope(``float` `x1, ``float` `y1, ``float` `x2, ` `                       ``float` `y2) ` `    ``{ ` `        ``if` `(x2 - x1 != ``0``) ` `            ``return` `(y2 - y1) / (x2 - x1); ` `        ``return` `Integer.MAX_VALUE; ` `    ``} ` `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` `        ``float` `x1 = ``4``, y1 = ``2``; ` `        ``float` `x2 = ``2``, y2 = ``5``; ` `        ``System.out.println(``"Slope is: "` `                           ``+ slope(x1, y1, x2, y2)); ` `    ``} ` `}`

## Python

 `# Python program for slope of line ` `def` `slope(x1, y1, x2, y2): ` `    ``if``(x2 ``-` `x1 !``=` `0``): ` `      ``return` `(``float``)(y2``-``y1)``/``(x2``-``x1) ` `    ``return` `sys.maxint ` ` `  ` `  `# driver code ` `x1 ``=` `4` `y1 ``=` `2` `x2 ``=` `2` `y2 ``=` `5` `print` `"Slope is:"``, slope(x1, y1, x2, y2) `

## C#

 `using` `System; ` ` `  `public` `static` `class` `GFG { ` `    ``// C# program for slope of line ` ` `  `    ``// function to find the slope of a straight line ` `    ``public` `static` `float` `slope(``float` `x1, ``float` `y1, ``float` `x2, ` `                              ``float` `y2) ` `    ``{ ` `        ``if` `(x2 - x1 != 0F) { ` `            ``return` `(y2 - y1) / (x2 - x1); ` `        ``} ` `        ``return` `int``.MaxValue; ` `    ``} ` ` `  `    ``// driver code to check the above function ` `    ``internal` `static` `void` `Main() ` `    ``{ ` `        ``float` `x1 = 4F; ` `        ``float` `y1 = 2F; ` `        ``float` `x2 = 2F; ` `        ``float` `y2 = 5F; ` `        ``Console.Write(``"Slope is: "``); ` `        ``Console.Write(slope(x1, y1, x2, y2)); ` `    ``} ` `} ` ` `  `// The code is contributed by Aarti_Rathi`

## PHP

 ` `

## Javascript

 `// C Javascript program for slope of line ` ` `  `// function to find the slope of a straight line ` `function` `slope(x1, y1, x2, y2) ` `{ ` `    ``if` `(x2 - x1 != 0) ` `    ``{ ` `        ``return` `(y2 - y1) / (x2 - x1); ` `    ``} ` `    ``return` `Number.MAX_VALUE; ` `} ` ` `  `// driver code to check the above function ` `var` `x1 = 4; ` `var` `y1 = 2; ` `var` `x2 = 2; ` `var` `y2 = 5; ` `console.log(``"Slope is: "` `+ slope(x1, y1, x2, y2)); ` ` `  `// The code is contributed by Aarti_Rathi`

Output

`Slope is: -1.5`

Time Complexity: O(1)
Auxiliary Space: O(1)

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