Given a string, find the first repeated character in it. We need to find the character that occurs more than once and whose index of second occurrence is smallest. A variation of this question is discussed here.
Input: ch = “geeksforgeeks”
e is the first element that repeats
Input: str = “hello geeks”
l is the first element that repeats
Simple Solution: The solution is to run two nested loops. Start traversing from left side. For every character, check if it repeats or not. If the character repeats, increment count of repeating characters. When the count becomes K, return the character.
Time Complexity of this solution is O(n2)
We can Use Sorting to solve the problem in O(n Log n) time. Following are detailed steps.
- Copy the given array to an auxiliary array temp.
- Sort the temp array using a O(N log N) time sorting algorithm.
- Scan the input array from left to right. For every element, count its occurrences in temp using binary search. As soon as we find a character that occurs more than once, we return the character.
This step can be done in O(N Log N) time.
An efficient solution is to use Hashing to solve this in O(N) time on average.
- Create an empty hash.
- Scan each character of input string and insert values to each keys in the hash.
- When any character appears more than once, hash key value is increment by 1, and return the character.
Below image is a dry run of the above approach:
Below is the implementation of the above approach:
Similar Problem: finding first non-repeated character in a string.
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