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# Evaluation order of operands

• Difficulty Level : Easy
• Last Updated : 31 Mar, 2021

Consider the below program.

## C++

 `// C++ implementation``#include ``using` `namespace` `std;``int` `x = 0;` `int` `f1()``{``    ``x = 5;``    ``return` `x;``}` `int` `f2()``{``    ``x = 10;``    ``return` `x;``}` `int` `main()``{``    ``int` `p = f1() + f2();``    ``cout << (``"%d "``, x);``    ``getchar``();``    ``return` `0;``}`

## C

 `#include ``int` `x = 0;` `int` `f1()``{``    ``x = 5;``    ``return` `x;``}` `int` `f2()``{``    ``x = 10;``    ``return` `x;``}` `int` `main()``{``    ``int` `p = f1() + f2();``    ``printf``(``"%d "``, x);``    ``getchar``();``    ``return` `0;``}`

## Java

 `class` `GFG {` `    ``static` `int` `x = ``0``;` `    ``static` `int` `f1()``    ``{``        ``x = ``5``;``        ``return` `x;``    ``}` `    ``static` `int` `f2()``    ``{``        ``x = ``10``;``        ``return` `x;``    ``}` `    ``public` `static` `void` `main(String[] args)``    ``{``        ``int` `p = f1() + f2();``        ``System.out.printf(``"%d "``, x);``    ``}``}` `// This code is contributed by Rajput-Ji`

## Python3

 `# Python3 implementation of the above approach``class` `A():``    ``x ``=` `0``;` `    ``def` `f1():``        ``A.x ``=` `5``;``        ``return` `A.x;` `    ``def` `f2():``        ``A.x ``=` `10``;``        ``return` `A.x;``        ` `# Driver Code``p ``=` `A.f1() ``+` `A.f2();``print``(A.x);` `# This code is contributed by mits`

## C#

 `// C# implementation of the above approach``using` `System;` `class` `GFG {` `    ``static` `int` `x = 0;` `    ``static` `int` `f1()``    ``{``        ``x = 5;``        ``return` `x;``    ``}` `    ``static` `int` `f2()``    ``{``        ``x = 10;``        ``return` `x;``    ``}` `    ``// Driver code``    ``public` `static` `void` `Main(String[] args)``    ``{``        ``int` `p = f1() + f2();``        ``Console.WriteLine(``"{0} "``, x);``    ``}``}` `// This code has been contributed``// by 29AjayKumar`

## PHP

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## Javascript

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Output:

`10`

What would the output of the above program – ‘5’ or ’10’?
The output is undefined as the order of evaluation of f1() + f2() is not mandated by standard. The compiler is free to first call either f1() or f2(). Only when equal level precedence operators appear in an expression, the associativity comes into picture. For example, f1() + f2() + f3() will be considered as (f1() + f2()) + f3(). But among first pair, which function (the operand) evaluated first is not defined by the standard.
Thanks to Venki for suggesting the solution.