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Enlightened Numbers

Last Updated : 22 Apr, 2021
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Enlightened Number is a composite number N if it begins with the concatenation of its distinct prime factors
Some Enlightened numbers are: 
 

250, 256, 2048, 2176, 2304, 2500, 2560… 
 

Check if N is an Enlightened number

Given a number N, the task is to check if N is an Enlightened Number or not. If N is an Enlightened Number then print “Yes” else print “No”.
Examples: 
 

Input: N = 2500 
Output: Yes 
Explanation: 
factorization of 25 = 2^2 * 5^4 
and N begins also with ’25’.
Input: N = 25 
Output: No 
 

Approach: The idea is to check if N is composite or not, If not composite return false otherwise concatenate all the distinct prime factors of the number N in a string. Also, convert the number N to string. Now we just have to check if the concatenation of distinct prime factors is a prefix of the number N or not, If it is then print “Yes” else print “No”.
Below is the implementation of the above approach:
 

C++




// C++ implementation of the
// above approach
#include<iostream>
#include<math.h>
using namespace std;
 
// Function to check if N is a
// Composite Number
bool isComposite(int n)
{
     
    // Corner cases
    if (n <= 3)
        return false;
 
    // This is checked so that we can skip
    // middle five numbers in below loop
    if (n % 2 == 0 || n % 3 == 0)
        return true;
         
    for(int i = 5; i * i <= n; i = i + 6)
        if (n % i == 0 || n % (i + 2) == 0)
            return true;
             
    return false;
}
 
// Function to return concatenation of
// distinct prime factors of a given number n
int concatenatePrimeFactors(int n)
{
    char concatenate;
 
    // Handle prime factor 2 explicitly
    // so that can optimally handle
    // other prime factors.
    if (n % 2 == 0)
    {
        concatenate += char(2);
        while (n % 2 == 0)
            n = n / 2;
    }
 
    // n must be odd at this point.
    // So we can skip one element
    // (Note i = i + 2)
    for(int i = 3; i <= sqrt(n); i = i + 2)
    {
        // While i divides n, print
        // i and divide n
        if (n % i == 0)
        {
            concatenate += i;
            while (n % i == 0)
                n = n / i;
        }
    }
     
    // This condition is to handle the
    // case when n is a prime number
    // greater than 2
    if (n > 2)
        concatenate += n;
         
    return concatenate;
}
 
// Function to check if a number is
// is an enlightened number
bool isEnlightened(int N)
{
     
    // Number should not be prime
    if (!isComposite(N))
        return false;
         
    // Converting N to string
    char num = char(N);
     
    // Function call
    char prefixConc = concatenatePrimeFactors(N);
     
    return int(prefixConc);
}
 
// Driver code
int main()
{
    int n = 250;
     
    if (isEnlightened(n))
        cout << "Yes";
    else
        cout << "No";
}
 
// This code is contributed by adityakumar27200


Java




// Java implementation of the
// above approach
 
import java.util.*;
 
class GFG {
 
    // Function to check if N is a
    // Composite Number
    static boolean isComposite(int n)
    {
        // Corner cases
        if (n <= 3)
            return false;
 
        // This is checked so that we can skip
        // middle five numbers in below loop
        if (n % 2 == 0 || n % 3 == 0)
            return true;
 
        for (int i = 5; i * i <= n; i = i + 6)
            if (n % i == 0 || n % (i + 2) == 0)
                return true;
 
        return false;
    }
 
    // Function to return concatenation of
    // distinct prime factors of a given number n
    static String concatenatePrimeFactors(int n)
    {
        String concatenate = "";
 
        // Handle prime factor 2 explicitly
        // so that can optimally handle
        // other prime factors.
        if (n % 2 == 0) {
            concatenate += "2";
            while (n % 2 == 0)
                n = n / 2;
        }
 
        // n must be odd at this point.
        // So we can skip one element
        // (Note i = i + 2)
        for (int i = 3; i <= Math.sqrt(n); i = i + 2) {
            // While i divides n, print
            // i and divide n
            if (n % i == 0) {
                concatenate += i;
                while (n % i == 0)
                    n = n / i;
            }
        }
 
        // This condition is to handle the
        // case when n is a prime number
        // greater than 2
        if (n > 2)
            concatenate += n;
 
        return concatenate;
    }
 
    // Function to check if a number is
    // is an enlightened number
    static boolean isEnlightened(int N)
    {
        // number should not be prime
        if (!isComposite(N))
            return false;
 
        // converting N to string
        String num = String.valueOf(N);
        // function call
        String prefixConc
            = concatenatePrimeFactors(N);
 
        return num.startsWith(prefixConc);
    }
 
    // Driver code
    public static void main(String args[])
    {
 
        int n = 250;
        if (isEnlightened(n))
            System.out.println("Yes");
        else
            System.out.println("No");
    }
}


Python3




# Python3 implementation of the
# above approach
import math
 
# Function to check if N is a
# Composite Number
def isComposite(n):
     
    # Corner cases
    if n <= 3:
        return False
     
    # This is checked so that we can skip
    # middle five numbers in below loop
    if (n % 2 == 0 or n % 3 == 0):
        return True
     
    i = 5
    while(i * i <= n):
        if(n % i == 0 or n % (i + 2) == 0):
            return True
        i = i + 6
         
    return False
 
# Function to return concatenation of
# distinct prime factors of a given number n    
def concatenatePrimeFactors(n):
     
    concatenate = ""
     
    # Handle prime factor 2 explicitly
    # so that can optimally handle
    # other prime factors.
    if(n % 2 == 0):
        concatenate += "2"
         
        while(n % 2 == 0):
            n = int(n / 2)
 
    # n must be odd at this point.
    # So we can skip one element
    # (Note i = i + 2)
    i = 3
    while(i <= int(math.sqrt(n))):
         
        # While i divides n, print
        # i and divide n
        if(n % i == 0):
            concatenate += str(i)
             
            while(n % i == 0):
                n = int(n / i)
 
        i = i + 2
         
    # This condition is to handle the
    # case when n is a prime number
    # greater than 2    
    if(n > 2):
        concatenate += str(n)
         
    return concatenate
 
# Function to check if a number is
# is an enlightened number
def isEnlightened(N):
     
    # Number should not be prime
    if(not isComposite(N)):
        return False
     
    # Converting N to string    
    num = str(N)
     
    # Function call
    prefixConc = concatenatePrimeFactors(N)
     
    return int(prefixConc)
 
# Driver code   
if __name__=="__main__":
     
    n = 250
     
    if(isEnlightened(n)):
        print("Yes")
    else:
        print("No")
 
# This code is contributed by adityakumar27200


C#




// C# implementation of the
// above approach
using System;
 
class GFG{
 
// Function to check if N is a
// Composite Number
static bool isComposite(int n)
{
     
    // Corner cases
    if (n <= 3)
        return false;
 
    // This is checked so that we can skip
    // middle five numbers in below loop
    if (n % 2 == 0 || n % 3 == 0)
        return true;
 
    for(int i = 5; i * i <= n; i = i + 6)
       if (n % i == 0 || n % (i + 2) == 0)
           return true;
 
    return false;
}
 
// Function to return concatenation of
// distinct prime factors of a given number n
static String concatenatePrimeFactors(int n)
{
    String concatenate = "";
 
    // Handle prime factor 2 explicitly
    // so that can optimally handle
    // other prime factors.
    if (n % 2 == 0)
    {
        concatenate += "2";
        while (n % 2 == 0)
            n = n / 2;
    }
 
    // n must be odd at this point.
    // So we can skip one element
    // (Note i = i + 2)
    for(int i = 3; i <= Math.Sqrt(n);
            i = i + 2)
    {
         
       // While i divides n, print
       // i and divide n
       if (n % i == 0)
       {
           concatenate += i;
           while (n % i == 0)
               n = n / i;
       }
    }
     
    // This condition is to handle the
    // case when n is a prime number
    // greater than 2
    if (n > 2)
        concatenate += n;
 
    return concatenate;
}
 
// Function to check if a number is
// is an enlightened number
static bool isEnlightened(int N)
{
     
    // Number should not be prime
    if (!isComposite(N))
        return false;
 
    // Converting N to string
    String num = String.Join("", N);
     
    // Function call
    String prefixConc = concatenatePrimeFactors(N);
 
    return num.StartsWith(prefixConc);
}
 
// Driver code
public static void Main(String []args)
{
    int n = 250;
     
    if (isEnlightened(n))
        Console.WriteLine("Yes");
    else
        Console.WriteLine("No");
}
}
 
// This code is contributed by Rajput-Ji


Javascript




<script>
 
// Javascript implementation of the
// above approach
 
// Function to check if N is a
// Composite Number
function isComposite(n)
{
     
    // Corner cases
    if (n <= 3)
        return false;
 
    // This is checked so that we can skip
    // middle five numbers in below loop
    if (n % 2 == 0 || n % 3 == 0)
        return true;
         
    for(var i = 5; i * i <= n; i = i + 6)
        if (n % i == 0 || n % (i + 2) == 0)
            return true;
             
    return false;
}
 
// Function to return concatenation of
// distinct prime factors of a given number n
function concatenatePrimeFactors(n)
{
    var concatenate;
 
    // Handle prime factor 2 explicitly
    // so that can optimally handle
    // other prime factors.
    if (n % 2 == 0)
    {
        concatenate += "2";
        while (n % 2 == 0)
            n = parseInt(n / 2);
    }
 
    // n must be odd at this point.
    // So we can skip one element
    // (Note i = i + 2)
    for(var i = 3; i <= Math.sqrt(n); i = i + 2)
    {
        // While i divides n, print
        // i and divide n
        if (n % i == 0)
        {
            concatenate += i;
            while (n % i == 0)
                n = parseInt(n / i);
        }
    }
     
    // This condition is to handle the
    // case when n is a prime number
    // greater than 2
    if (n > 2)
        concatenate += n;
         
    return concatenate;
}
 
// Function to check if a number is
// is an enlightened number
function isEnlightened(N)
{
     
    // Number should not be prime
    if (!isComposite(N))
        return false;
         
    // Converting N to string
    var num = (N.toString());
     
    // Function call
    var prefixConc = concatenatePrimeFactors(N);
     
    return (prefixConc);
}
 
// Driver code
var n = 250;
 
if (isEnlightened(n))
    document.write( "Yes");
else
    document.write( "No");
 
 
</script>


Output: 

Yes

 

Time Complexity: O(n) 
 



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