Print all distinct permutation of a string having duplicates.
Input : ABCA Output : AABC AACB ABAC ABCA ACBA ACAB BAAC BACA BCAA CABA CAAB CBAA
An algorithm to print all distinct permutations has already been discussed here. Here we’ll discuss one more approach to do the same. Recall first how we print permutations without any duplicates in the input string. It is given here. Let’s now take the case of the string “ABAC”. While generating permutations, let’s say we are at index = 0, swap it with all elements after it. When we reach at i=2, we see that in the string s[index…i-1], there was an index which is equal to s[i]. Thus, swapping it will produce repeated permutations. Thus, we don’t swap it. The below explains it better.
Illustration : Let us understand with below example.
i = 0 1 2 3 A B A C index = 0, s = A Start swapping s[index] with s[i] following it: i = index + 1 = 1 Since s[index] != s[i], swap and recur. i = 2, s[index] == s[i], don't swap i = 3, s[index] != s[i], swap and recur.
Below code does the same.
ABCA ABAC ACBA ACAB AACB AABC BACA BAAC BCAA CBAA CABA CAAB
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