Given a linked list of n nodes which is first sorted, then rotated by k elements. Find the value of k.
The idea is to traverse singly linked list to check condition whether current node value is greater than value of next node. If the given condition is true, then break the loop. Otherwise increase the counter variable and increase the node by node->next. Below is the implementation of this approach.
C++
// Program for count number of rotations in // sorted linked list. #include <bits/stdc++.h> using namespace std; /* Linked list node */struct Node { int data; struct Node* next; }; // Function that count number of // rotation in singly linked list. int countRotation(struct Node* head) { // declare count variable and assign it 1. int count = 0; // declare a min variable and assign to // data of head node. int min = head->data; // check that while head not equal to NULL. while (head != NULL) { // if min value is greater then head->data // then it breaks the while loop and // return the value of count. if (min > head->data) break; count++; // head assign the next value of head. head = head->next; } return count; } // Function to push element in linked list. void push(struct Node** head, int data) { // Allocate dynamic memory for newNode. struct Node* newNode = new Node; // Assign the data into newNode. newNode->data = data; // newNode->next assign the address of // head node. newNode->next = (*head); // newNode become the headNode. (*head) = newNode; } // Display linked list. void printList(struct Node* node) { while (node != NULL) { printf("%d ", node->data); node = node->next; } } // Driver functions int main() { // Create a node and initialize with NULL struct Node* head = NULL; // push() insert node in linked list. // 15 -> 18 -> 5 -> 8 -> 11 -> 12 push(&head, 12); push(&head, 11); push(&head, 8); push(&head, 5); push(&head, 18); push(&head, 15); printList(head); cout << endl; cout << "Linked list rotated elements: "; // Function call countRotation() cout << countRotation(head) << endl; return 0; } |
Python3
# Program for count number of rotations in # sorted linked list. # Linked list node class Node: def __init__(self, data): self.data = data self.next = None # Function that count number of # rotation in singly linked list. def countRotation(head): # Declare count variable and assign it 1. count = 0 # Declare a min variable and assign to # data of head node. min = head.data # Check that while head not equal to None. while (head != None): # If min value is greater then head->data # then it breaks the while loop and # return the value of count. if (min > head.data): break count += 1 # head assign the next value of head. head = head.next return count # Function to push element in linked list. def push(head, data): # Allocate dynamic memory for newNode. newNode = Node(data) # Assign the data into newNode. newNode.data = data # newNode->next assign the address of # head node. newNode.next = (head) # newNode become the headNode. (head) = newNode return head # Display linked list. def printList(node): while (node != None): print(node.data, end = ' ') node = node.next # Driver code if __name__=='__main__': # Create a node and initialize with None head = None # push() insert node in linked list. # 15 -> 18 -> 5 -> 8 -> 11 -> 12 head = push(head, 12) head = push(head, 11) head = push(head, 8) head = push(head, 5) head = push(head, 18) head = push(head, 15) printList(head); print() print("Linked list rotated elements: ", end = '') # Function call countRotation() print(countRotation(head)) # This code is contributed by rutvik_56 |
15 18 5 8 11 12 Linked list rotated elements: 2
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