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Count of primes below N which can be expressed as the sum of two primes
• Last Updated : 16 Apr, 2021

Given an integer N, the task is to find the count of all the primes below N which can be expressed as the sum of two primes.
Examples:

Input: N = 6
Output:
5 is the only such prime below 6.
2 + 3 = 5.
Input: N = 11
Output:

Approach: Create an array prime[] where prime[i] will store whether i is prime or not using Sieve of Eratosthenes. Now for every prime from the range [1, N – 1], check whether it can be expressed as the sum of two primes using the approach discussed here.
Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach``#include ``using` `namespace` `std;` `const` `int` `MAX = 100005;``bool` `prime[MAX];` `// Function for Sieve of Eratosthenes``void` `SieveOfEratosthenes()``{``    ``memset``(prime, ``true``, ``sizeof``(prime));` `    ``// false here indicates``    ``// that it is not prime``    ``prime[0] = ``false``;``    ``prime[1] = ``false``;` `    ``for` `(``int` `p = 2; p * p <= MAX; p++) {` `        ``// If prime[p] is not changed,``        ``// then it is a prime``        ``if` `(prime[p]) {` `            ``// Update all multiples of p,``            ``// set them to non-prime``            ``for` `(``int` `i = p * 2; i <= MAX; i += p)``                ``prime[i] = ``false``;``        ``}``    ``}``}` `// Function to return the count of primes``// less than or equal to n which can be``// expressed as the sum of two primes``int` `countPrimes(``int` `n)``{``    ``SieveOfEratosthenes();` `    ``// To store the required count``    ``int` `cnt = 0;` `    ``for` `(``int` `i = 2; i < n; i++) {` `        ``// If the integer is prime and it``        ``// can be expressed as the sum of``        ``// 2 and a prime number``        ``if` `(prime[i] && prime[i - 2])``            ``cnt++;``    ``}` `    ``return` `cnt;``}` `// Driver code``int` `main()``{``    ``int` `n = 11;` `    ``cout << countPrimes(n);` `    ``return` `0;``}`

## Java

 `// Java implementation of the approach``class` `GFG``{` `static` `int` `MAX = ``100005``;``static` `boolean` `[]prime = ``new` `boolean``[MAX];` `// Function for Sieve of Eratosthenes``static` `void` `SieveOfEratosthenes()``{` `    ``for` `(``int` `i = ``0``; i < MAX; i++)``        ``prime[i] = ``true``;` `    ``// false here indicates``    ``// that it is not prime``    ``prime[``0``] = ``false``;``    ``prime[``1``] = ``false``;` `    ``for` `(``int` `p = ``2``; p * p < MAX; p++)``    ``{``        ``// If prime[p] is not changed,``        ``// then it is a prime``        ``if` `(prime[p])``        ``{``            ``// Update all multiples of p,``            ``// set them to non-prime``            ``for` `(``int` `i = p * ``2``; i < MAX; i += p)``                ``prime[i] = ``false``;``        ``}``    ``}``}` `// Function to return the count of primes``// less than or equal to n which can be``// expressed as the sum of two primes``static` `int` `countPrimes(``int` `n)``{``    ``SieveOfEratosthenes();` `    ``// To store the required count``    ``int` `cnt = ``0``;` `    ``for` `(``int` `i = ``2``; i < n; i++)``    ``{``        ``// If the integer is prime and it``        ``// can be expressed as the sum of``        ``// 2 and a prime number``        ``if` `(prime[i] && prime[i - ``2``])``            ``cnt++;``    ``}``    ``return` `cnt;``}` `// Driver code``public` `static` `void` `main(String[] args)``{``    ``int` `n = ``11``;` `    ``System.out.print(countPrimes(n));``}``}` `// This code is contributed by 29AjayKumar`

## Python3

 `# Python3 implementation of the approach``MAX` `=` `100005``prime ``=` `[``True` `for` `i ``in` `range``(``MAX``)]` `# Function for Sieve of Eratosthenes``def` `SieveOfEratosthenes():` `    ``# False here indicates``    ``# that it is not prime``    ``prime[``0``] ``=` `False``    ``prime[``1``] ``=` `False` `    ``for` `p ``in` `range``(``MAX``):` `        ``if``(p ``*` `p > ``MAX``):``            ``break` `        ``# If prime[p] is not changed,``        ``# then it is a prime``        ``if` `(prime[p]):` `            ``# Update all multiples of p,``            ``# set them to non-prime``            ``for` `i ``in` `range``(``2` `*` `p, ``MAX``, p):``                ``prime[i] ``=` `False` `# Function to return the count of primes``# less than or equal to n which can be``# expressed as the sum of two primes``def` `countPrimes(n):``    ``SieveOfEratosthenes()` `    ``# To store the required count``    ``cnt ``=` `0` `    ``for` `i ``in` `range``(``2``, n):` `        ``# If the integer is prime and it``        ``# can be expressed as the sum of``        ``# 2 and a prime number``        ``if` `(prime[i] ``and` `prime[i ``-` `2``]):``            ``cnt ``+``=` `1` `    ``return` `cnt` `# Driver code``n ``=` `11` `print``(countPrimes(n))` `# This code is contributed by Mohit Kumar`

## C#

 `    ``// C# implementation of the approach``using` `System;` `class` `GFG``{``static` `int` `MAX = 100005;``static` `bool` `[]prime = ``new` `bool``[MAX];` `// Function for Sieve of Eratosthenes``static` `void` `SieveOfEratosthenes()``{``    ``for` `(``int` `i = 0; i < MAX; i++)``        ``prime[i] = ``true``;` `    ``// false here indicates``    ``// that it is not prime``    ``prime[0] = ``false``;``    ``prime[1] = ``false``;` `    ``for` `(``int` `p = 2; p * p < MAX; p++)``    ``{``        ``// If prime[p] is not changed,``        ``// then it is a prime``        ``if` `(prime[p])``        ``{``            ``// Update all multiples of p,``            ``// set them to non-prime``            ``for` `(``int` `i = p * 2; i < MAX; i += p)``                ``prime[i] = ``false``;``        ``}``    ``}``}` `// Function to return the count of primes``// less than or equal to n which can be``// expressed as the sum of two primes``static` `int` `countPrimes(``int` `n)``{``    ``SieveOfEratosthenes();` `    ``// To store the required count``    ``int` `cnt = 0;` `    ``for` `(``int` `i = 2; i < n; i++)``    ``{``        ``// If the integer is prime and it``        ``// can be expressed as the sum of``        ``// 2 and a prime number``        ``if` `(prime[i] && prime[i - 2])``            ``cnt++;``    ``}``    ``return` `cnt;``}` `// Driver code``public` `static` `void` `Main(String[] args)``{``    ``int` `n = 11;` `    ``Console.Write(countPrimes(n));``}``}` `// This code is contributed by Rajput-Ji`

## Javascript

 ``
Output:
`2`

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