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Check if a prime number can be expressed as sum of two Prime Numbers

  • Last Updated : 07 Apr, 2021

Given a prime number N  . The task is to check if it is possible to express N  as sum of two separate prime numbers.
Note: The range of N is less than 108.

Examples: 

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Input : N = 13
Output : Yes
Explanation : The number 13 can be written as 11 + 2, 
here 11 and 2 are both prime.

Input : N = 11
Output : No

Simple Solution: A simple solution is to create a sieve to store all the prime numbers less than the number N. Then run a loop from 1 to N and check whether i  and n-i  are both prime or not. If yes then print Yes, else No.

Efficient solution: Apart from 2, all of the prime numbers are odd. So it is not possible to represent a prime number (which is odd) to be written as a sum of two odd prime numbers, so we are sure that one of the two prime number should be 2. So we have to check whether n-2 is prime or not. If it holds we print Yes else No.
For example, if the number is 19 then we have to check whether 19-2 = 17 is a prime number or not. If 17 is a prime number then print yes otherwise print no.

Below is the implementation of the above approach: 

C++




// C++ program to check if a prime number
// can be expressed as sum of
// two Prime Numbers
#include <bits/stdc++.h>
using namespace std;
 
// Function to check whether a number
// is prime or not
bool isPrime(int n)
{
    if (n <= 1)
        return false;
 
    for (int i = 2; i <= sqrt(n); i++) {
        if (n % i == 0)
            return false;
    }
 
    return true;
}
 
// Function to check if a prime number
// can be expressed as sum of
// two Prime Numbers
bool isPossible(int N)
{
    // if the number is prime,
    // and number-2 is also prime
    if (isPrime(N) && isPrime(N - 2))
        return true;
    else
        return false;
}
 
// Driver code
int main()
{
    int n = 13;
 
    if (isPossible(n))
        cout << "Yes";
    else
        cout << "No";
 
    return 0;
}

Java




// Java program to check if a prime number
// can be expressed as sum of
// two Prime Numbers
 
public class GFG{
     
    // Function to check whether a number
    // is prime or not
    static boolean isPrime(int n)
    {
        if (n <= 1)
            return false;
     
        for (int i = 2; i <= Math.sqrt(n); i++) {
            if (n % i == 0)
                return false;
        }
     
        return true;
    }
     
    // Function to check if a prime number
    // can be expressed as sum of
    // two Prime Numbers
    static boolean isPossible(int N)
    {
        // if the number is prime,
        // and number-2 is also prime
        if (isPrime(N) && isPrime(N - 2))
            return true;
        else
            return false;
    }
     
     // Driver code
     public static void main(String []args){
          
        int n = 13;
     
        if (isPossible(n) == true)
            System.out.println("Yes");
        else
            System.out.println("No");
     }
     // This code is contributed by ANKITRAI1
}

Python3




# Python3 program to check if a prime
# number can be expressed as sum of
# two Prime Numbers
import math
 
# Function to check whether a number
# is prime or not
def isPrime(n):
    if n <= 1:
        return False
     
    if n == 2:
        return True
         
    if n%2 == 0:
        return False
         
    for i in range(3, int(math.sqrt(n))+1, 2):
        if n%i == 0:
            return False
    return True
 
# Function to check if a prime number
# can be expressed as sum of
# two Prime Numbers
def isPossible(n):
 
    # if the number is prime,
    # and number-2 is also prime
    if isPrime(n) and isPrime(n - 2):
        return True
    else:
        return False
 
# Driver code
n = 13
if isPossible(n) == True:
    print("Yes")
else:
    print("No")
     
# This code is contributed by Shrikant13

C#




// C# program to check if a prime
// number can be expressed as sum
// of two Prime Numbers
using System;
 
class GFG
{
 
// Function to check whether a
// number is prime or not
static bool isPrime(int n)
{
    if (n <= 1)
        return false;
 
    for (int i = 2;
             i <= Math.Sqrt(n); i++)
    {
        if (n % i == 0)
            return false;
    }
 
    return true;
}
 
// Function to check if a prime
// number can be expressed as sum
// of two Prime Numbers
static bool isPossible(int N)
{
    // if the number is prime,
    // and number-2 is also prime
    if (isPrime(N) && isPrime(N - 2))
        return true;
    else
        return false;
}
 
// Driver code
public static void Main()
{
    int n = 13;
 
    if (isPossible(n) == true)
        Console.Write("Yes");
    else
        Console.Write("No");
}
}
 
// This code is contributed
// by ChitraNayal

PHP




<?php
// PHP program to check if a prime
// number can be expressed as sum
// of two Prime Numbers
 
// Function to check whether a
// number is prime or not
function isPrime($n)
{
    if ($n <= 1)
        return false;
 
    for ($i = 2; $i <= sqrt($n); $i++)
    {
        if ($n % $i == 0)
            return false;
    }
 
    return true;
}
 
// Function to check if a prime
// number can be expressed as sum
// of two Prime Numbers
function isPossible($N)
{
    // if the number is prime,
    // and number-2 is also prime
    if (isPrime($N) && isPrime($N - 2))
        return true;
    else
        return false;
}
 
// Driver code
$n = 13;
 
if (isPossible($n))
    echo ("Yes");
else
    echo("No");
 
// This code is contributed
// by Shivi_Aggarwal
?>

Javascript




<script>
 
// Javascript program to check if a
// prime number can be expressed as
// sum of two Prime Numbers
 
// Function to check whether a number
// is prime or not
function isPrime(n)
{
    if (n <= 1)
        return false;
 
    for(var i = 2; i <= parseInt(Math.sqrt(n)); i++)
    {
        if (n % i == 0)
            return false;
    }
 
    return true;
}
 
// Function to check if a prime number
// can be expressed as sum of
// two Prime Numbers
function isPossible(N)
{
     
    // If the number is prime,
    // and number-2 is also prime
    if (isPrime(N) && isPrime(N - 2))
        return true;
    else
        return false;
}
 
// Driver code
var n = 13;
if (isPossible(n))
    document.write("Yes");
else
    document.write("No");
     
// This code is contributed by noob2000
 
</script>
Output: 
Yes

 




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