Count of alphabets having ASCII value less than and greater than k

Given a string, the task is to count the number of alphabets having ASCII value less than and greater than or equal to a given integer k.

Examples:

Input: str = "GeeksForGeeks", k = 90
Output: 3, 10
G, F, G have ascii values less than 90.
e, e, k, s, o, r, e, e, k, s have ascii values 
greater than or equal to 90

Input: str = "geeksforgeeks", k = 90
Output: 0, 13

Approach: Start traversing the string and check if the current character has ASCII value less than k. If yes then increment the count.
So, Remaining characters will have ASCII values greater than or equal to k. So, print len_of_String – count for characters with ASCII values greater than or equal to k.



Below is the implementation of the above approach:

C++

filter_none

edit
close

play_arrow

link
brightness_4
code

// C++ implementation of the above approach
#include <bits/stdc++.h>
using namespace std;
  
// Function to count the number of
// characters whose ascii value is less than k
int CountCharacters(string str, int k)
{
    // Initialising the count to 0
    int cnt = 0;
  
    int len = str.length();
    for (int i = 0; i < len; i++) {
        // Incrementing the count
        // if the value is less
        if (str[i] < k)
            cnt++;
    }
  
    // return the count
    return cnt;
}
  
// Driver code
int main()
{
    string str = "GeeksForGeeks";
    int k = 90;
  
    int count = CountCharacters(str, k);
    cout << "Characters with ASCII values"
            " less than K are "
         << count;
  
    cout << "\nCharacters with ASCII values"
            " greater than or equal to K are "
         << str.length() - count;
  
    return 0;
}

chevron_right


Java

filter_none

edit
close

play_arrow

link
brightness_4
code

// Java implementation of the above approach
import java.util.*;
  
class GFG {
      
// Function to count the number of
// characters whose ascii value is less than k
static int CountCharacters(String str, int k)
{
    // Initialising the count to 0
    int cnt = 0;
  
    int len = str.length();
    for (int i = 0; i < len; i++) {
        // Incrementing the count
        // if the value is less
        if (((int)str.charAt(i)) < k)
            cnt++;
    }
  
    // return the count
    return cnt;
}
  
// Driver code
public static void main(String args[])
{
    String str = "GeeksForGeeks";
    int k = 90;
  
    int count = CountCharacters(str, k);
    System.out.println("Characters with ASCII values less than K are "+count);
  
    System.out.println("Characters with ASCII values greater than or equal to K are "+(str.length() - count));
  
}
}

chevron_right


Python3

filter_none

edit
close

play_arrow

link
brightness_4
code

# Python3 implementation of the
# above approach
  
# Function to count the number of
# characters whose ascii value is 
# less than k
def CountCharacters(str, k):
  
    # Initialising the count to 0
    cnt = 0
  
    l = len(str)
    for i in range(l):
          
        # Incrementing the count
        # if the value is less
        if (ord(str[i]) < k):
            cnt += 1
  
    # return the count
    return cnt
  
# Driver code
if __name__ == "__main__":
  
    str = "GeeksForGeeks"
    k = 90
  
    count = CountCharacters(str, k)
    print ("Characters with ASCII values",
                "less than K are", count)
  
    print ("Characters with ASCII values",
           "greater than or equal to K are",
                           len(str) - count)
  
# This code is contributed by ita_c

chevron_right


C#

filter_none

edit
close

play_arrow

link
brightness_4
code

// C# implementation of the above approach 
using System;
class GFG { 
      
// Function to count the number of 
// characters whose ascii value is less than k 
static int CountCharacters(String str, int k) 
    // Initialising the count to 0 
    int cnt = 0; 
  
    int len = str.Length; 
    for (int i = 0; i < len; i++) 
    
        // Incrementing the count 
        // if the value is less 
        if (((int)str[i]) < k) 
            cnt++; 
    
  
    // return the count 
    return cnt; 
  
// Driver code 
public static void Main() 
    String str = "GeeksForGeeks"
    int k = 90; 
    int count = CountCharacters(str, k); 
    Console.WriteLine("Characters with ASCII values" +
                        "less than K are " + count); 
  
    Console.WriteLine("Characters with ASCII values greater" +
                    "than or equal to K are "+(str.Length - count)); 
  
// This code is contributed by princiraj1992

chevron_right


PHP

filter_none

edit
close

play_arrow

link
brightness_4
code

<?php
// PHP implementation of the above approach
  
// Function to count the number of
// characters whose ascii value is less than k
function CountCharacters($str, $k)
{
    // Initialising the count to 0
    $cnt = 0;
  
    $len = strlen($str);
    for ($i = 0; $i < $len; $i++) 
    {
        // Incrementing the count
        // if the value is less
        if ($str[$i] < chr($k))
            $cnt += 1;
    }
  
    // return the count
    return $cnt;
}
  
// Driver code
$str = "GeeksForGeeks";
$k = 90;
  
$count = CountCharacters($str, $k);
echo("Characters with ASCII values"
       " less than K are " . $count);
  
echo("\nCharacters with ASCII values"
     " greater than or equal to K are "
                (strlen($str) - $count));
  
// This code contributed by Rajput-Ji
?>

chevron_right


Output:

Characters with ASCII values less than K are 3
Characters with ASCII values greater than or equal to K are 10

Time Complexity: O(N)



My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.