# Count the number of words having sum of ASCII values less than and greater than k

Given a string, the task is to count the number of words whose sum of Ascii values is less than and greater than or equal to given k.

Examples:

```Input: str = "Learn how to code", k = 400
Output:
Number of words having sum of ascii less than k = 2
Number of words having sum of ascii greater than or equal to k = 2

Input: str = "Geeks for Geeks", k = 400
Output:
Number of words having sum of ascii less than k = 1
Number of words having sum of ascii greater than or equal to k = 2
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: Count the number of words having the sum of ASCII values less than k and subtract it from the total number of words to get the number of words having ASCII values to the sum greater than or equal to k. Start traversing the string letter by letter and add the ASCII value to sum. If there is a space then increment the count if the sum is less than k and will also set the sum to 0.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the above approach ` `#include ` `using` `namespace` `std; ` ` `  `// Function to count the words ` `void` `CountWords(string str, ``int` `k) ` `{ ` `    ``// Sum of ascii values ` `    ``int` `sum = 0; ` ` `  `    ``int` `NumberOfWords = 0; ` ` `  `    ``// Number of words having ` `    ``// sum of ascii less than k ` `    ``int` `counter = 0; ` ` `  `    ``int` `len = str.length(); ` ` `  `    ``for` `(``int` `i = 0; i < len; ++i) { ` `        ``// If character is a space ` `        ``if` `(str[i] == ``' '``) { ` `            ``if` `(sum < k) ` `                ``counter++; ` ` `  `            ``sum = 0; ` `            ``NumberOfWords++; ` `        ``} ` `        ``else` `            ``// Add the ascii value to sum ` `            ``sum += str[i]; ` `    ``} ` ` `  `    ``// Handling the Last word separately ` `    ``NumberOfWords++; ` `    ``if` `(sum < k) ` `        ``counter++; ` ` `  `    ``cout << ``"Number of words having sum of ASCII"` `            ``" values less than k = "` `         ``<< counter << endl; ` `    ``cout << ``"Number of words having sum of ASCII values"` `            ``" greater than or equal to k = "` `         ``<< NumberOfWords - counter; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``string str = ``"Learn how to code"``; ` `    ``int` `k = 400; ` `    ``CountWords(str, k); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java implementation of the  ` `// above approach  ` `class` `GFG ` `{ ` `     `  `// Function to count the words  ` `static` `void` `CountWords(String str, ``int` `k)  ` `{ ` `    ``// Sum of ascii values  ` `    ``int` `sum = ``0``; ` ` `  `    ``int` `NumberOfWords = ``0``; ` ` `  `    ``// Number of words having  ` `    ``// sum of ascii less than k  ` `    ``int` `counter = ``0``; ` ` `  `    ``int` `len = str.length(); ` ` `  `    ``for` `(``int` `i = ``0``; i < len; ++i)  ` `    ``{ ` `        ``// If character is a space  ` `        ``if` `(str.charAt(i) == ``' '``)  ` `        ``{ ` `            ``if` `(sum < k) ` `            ``{ ` `                ``counter++; ` `            ``} ` ` `  `            ``sum = ``0``; ` `            ``NumberOfWords++; ` `        ``} ` `         `  `        ``else` `// Add the ascii value to sum  ` `        ``{ ` `            ``sum += str.charAt(i); ` `        ``} ` `    ``} ` ` `  `    ``// Handling the Last word separately  ` `    ``NumberOfWords++; ` `    ``if` `(sum < k) ` `    ``{ ` `        ``counter++; ` `    ``} ` ` `  `    ``System.out.println(``"Number of words having sum "` `+  ` `                    ``"of ASCII values less than k = "` `+  ` `                                             ``counter); ` `    ``System.out.println(``"Number of words having sum of "` `+  ` `           ``"ASCII values greater than or equal to k = "` `+ ` `                              ``(NumberOfWords - counter)); ` `} ` ` `  `// Driver code  ` `public` `static` `void` `main(String[] args)  ` `{ ` `    ``String str = ``"Learn how to code"``; ` `    ``int` `k = ``400``; ` `    ``CountWords(str, k); ` `} ` `} ` ` `  `// This code is contributed by RAJPUT-JI `

## Python 3

 `# Python 3 implementation of the  ` `# above approach ` ` `  `# Function to count the words ` `def` `CountWords(``str``, k): ` ` `  `    ``# Sum of ascii values ` `    ``sum` `=` `0` ` `  `    ``NumberOfWords ``=` `0` ` `  `    ``# Number of words having ` `    ``# sum of ascii less than k ` `    ``counter ``=` `0` ` `  `    ``l ``=` `len``(``str``) ` ` `  `    ``for` `i ``in` `range``(l): ` `         `  `        ``# If character is a space ` `        ``if` `(``str``[i] ``=``=` `' '``) : ` `            ``if` `(``sum` `< k): ` `                ``counter ``+``=` `1` ` `  `            ``sum` `=` `0` `            ``NumberOfWords ``+``=` `1` `         `  `        ``else``: ` `             `  `            ``# Add the ascii value to sum ` `            ``sum` `+``=` `ord``(``str``[i]) ` ` `  `    ``# Handling the Last word separately ` `    ``NumberOfWords ``+``=` `1` `    ``if` `(``sum` `< k): ` `        ``counter ``+``=` `1` ` `  `    ``print``(``"Number of words having sum of ASCII"``, ` `          ``"values less than k ="``, counter) ` `    ``print``(``"Number of words having sum of ASCII values"``, ` `                        ``"greater than or equal to k ="``,  ` `                               ``NumberOfWords ``-` `counter) ` ` `  `# Driver code ` `if` `__name__ ``=``=` `"__main__"``: ` `     `  `    ``str` `=` `"Learn how to code"` `    ``k ``=` `400` `    ``CountWords(``str``, k) ` ` `  `# This code is contributed  ` `# by ChitraNayal `

## C#

 `// C# implementation of the  ` `// above approach  ` `using` `System; ` ` `  `class` `GFG  ` `{ ` ` `  `// Function to count the words  ` `static` `void` `CountWords(String str, ` `                       ``int` `k)  ` `{ ` `    ``// Sum of ascii values  ` `    ``int` `sum = 0; ` ` `  `    ``int` `NumberOfWords = 0; ` ` `  `    ``// Number of words having  ` `    ``// sum of ascii less than k  ` `    ``int` `counter = 0; ` ` `  `    ``int` `len = str.Length; ` ` `  `    ``for` `(``int` `i = 0; i < len; ++i) ` `    ``{ ` `        ``// If character is a space  ` `        ``if` `(str[i]==``' '``) ` `        ``{ ` `            ``if` `(sum < k)  ` `            ``{ ` `                ``counter++; ` `            ``} ` ` `  `            ``sum = 0; ` `            ``NumberOfWords++; ` `        ``} ` `        ``else` `// Add the ascii value to sum  ` `        ``{ ` `            ``sum += str[i]; ` `        ``} ` `    ``} ` ` `  `    ``// Handling the Last word ` `    ``// separately  ` `    ``NumberOfWords++; ` `    ``if` `(sum < k)  ` `    ``{ ` `        ``counter++; ` `    ``} ` ` `  `    ``Console.WriteLine(``"Number of words having sum "` `+  ` `                      ``"of ASCII values less than k = "` `+  ` `                                               ``counter); ` `    ``Console.WriteLine(``"Number of words having sum of "` `+  ` `          ``"ASCII values greater than or equal to k = "` `+  ` `                             ``(NumberOfWords - counter)); ` `} ` ` `  `// Driver code  ` `public` `static` `void` `Main(String[] args) ` `{ ` `    ``String str = ``"Learn how to code"``; ` `    ``int` `k = 400; ` `    ``CountWords(str, k); ` `} ` `} ` ` `  `// This code is contributed by RAJPUT-JI `

## PHP

 ` `

Output:

```Number of words having sum of ASCII values less than k = 2
Number of words having sum of ASCII values greater than or equal to k = 2
```

Time Complexity: O(N)

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