# Count all 0s which are blocked by 1s in binary matrix

Given Binary matrix. Task is count all zeros which are surrounded by one (may not be immediate neighbor).
Note: here we are only taking four direction up, left, down, right.
Examples:

```Input :  Int M[][] = {{ 0, 1, 1, 0},
{ 1, 0, 0, 1},
{ 0, 1, 0, 1},
{ 1, 0, 1, 1}}
Output : 3
Explanation : All zeros which are surrounded
by 1 are (1, 1), (1, 2) and (2, 2)

```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Idea is based on the DFS.
First we remove all the zero value cells in the matrix which are reachable from boundary of Matrix using DFS. Note that any cell which is reachable from a boundary 0 cell is not surrounded by ones.

```  Int M[][] =  {{  0, 1, 1,  0},
{ 1, 0, 0, 1},
{ 0, 1, 1, 1},
{ 1,  0, 1, 1}}
All zero cell which are reachable from boundary are in read color.
```

After that we count all zeros which are left in binary matrix.
Below is the implementation of above idea.

## C++

 `// C++ program to count number of zeros ` `// surrounded by 1 ` `#include ` `using` `namespace` `std; ` `#define Row 4 ` `#define Col 5 ` `int` `r = { 0, 0, 1, -1 }; ` `int` `c = { 1, -1, 0, 0 }; ` ` `  `bool` `isSafe(``int` `x, ``int` `y, ``int` `M[][Col]) ` `{ ` `    ``if` `(x >= 0 && x <= Row && y >= 0 && ` `        ``y <= Col && M[x][y] == 0) ` `        ``return` `true``; ` `    ``return` `false``; ` `} ` ` `  `// DFS function to mark all reachable cells from ` `// (x, y) ` `void` `DFS(``int` `x, ``int` `y, ``int` `M[][Col]) ` `{ ` `    ``// make it's visited ` `    ``M[x][y] = 1; ` `    ``for` `(``int` `k = 0; k < 4; k++) ` `        ``if` `(isSafe(x + r[k], y + c[k], M)) ` `            ``DFS(x + r[k], y + c[k], M); ` `} ` ` `  `// function return count of 0's which are surrounded by 1 ` `int` `CountAllZero(``int` `M[][Col]) ` `{ ` `    ``// first we remove all zeros which are not ` `    ``// surrounded by 1 that means we only remove  ` `    ``// those zeros which are reachable from ` `    ``// any boundary of given matrix. ` `    ``for` `(``int` `i = 0; i < Col; i++) ` `        ``if` `(M[i] == 0) ` `            ``DFS(0, i, M); ` `    ``for` `(``int` `i = 0; i < Col; i++) ` `        ``if` `(M[Row - 1][i] == 0) ` `            ``DFS(Row - 1, i, M); ` `    ``for` `(``int` `i = 0; i < Row; i++) ` `        ``if` `(M[i] == 0) ` `            ``DFS(i, 0, M); ` `    ``for` `(``int` `i = 0; i < Row; i++) ` `        ``if` `(M[i][Col - 1] == 0) ` `            ``DFS(i, Col - 1, M); ` ` `  `    ``// count all zeros which are surrounded by 1 ` `    ``int` `result = 0; ` `    ``for` `(``int` `i = 0; i < Row; i++) ` `        ``for` `(``int` `j = 0; j < Col; j++) ` `            ``if` `(M[i][j] == 0) ` `                ``result++; ` `    ``return` `result; ` `} ` ` `  `// driver program to test above function ` `int` `main() ` `{ ` `    ``int` `M[][Col] = { { 1, 1, 1, 0, 1 }, ` `                     ``{ 1, 0, 0, 1, 0 }, ` `                     ``{ 1, 0, 1, 0, 1 }, ` `                     ``{ 0, 1, 1, 1, 1 } }; ` `    ``cout << CountAllZero(M) << endl; ` `    ``return` `0; ` `} `

## Java

 `// Java program to count number of zeros ` `// surrounded by 1 ` `class` `GFG { ` ` `  `    ``final` `static` `int` `Row = ``4``; ` `    ``final` `static` `int` `Col = ``5``; ` `    ``static` `int` `r[] = {``0``, ``0``, ``1``, -``1``}; ` `    ``static` `int` `c[] = {``1``, -``1``, ``0``, ``0``}; ` ` `  `    ``static` `boolean` `isSafe(``int` `x, ``int` `y, ``int` `M[][]) { ` `        ``if` `(x >= ``0` `&& x = ``0` `                ``&& y < Col && M[x][y] == ``0``) { ` `            ``return` `true``; ` `        ``} ` `        ``return` `false``; ` `    ``} ` ` `  `// DFS function to mark all reachable cells from ` `// (x, y) ` `    ``static` `void` `DFS(``int` `x, ``int` `y, ``int` `M[][]) { ` `        ``// make it's visited ` `        ``M[x][y] = ``1``; ` `        ``for` `(``int` `k = ``0``; k < ``4``; k++) { ` `            ``if` `(isSafe(x + r[k], y + c[k], M)) { ` `                ``DFS(x + r[k], y + c[k], M); ` `            ``} ` `        ``} ` `    ``} ` ` `  `// function return count of 0's which are surrounded by 1 ` `    ``static` `int` `CountAllZero(``int` `M[][]) { ` `        ``// first we remove all zeros which are not ` `        ``// surrounded by 1 that means we only remove  ` `        ``// those zeros which are reachable from ` `        ``// any boundary of given matrix. ` `        ``for` `(``int` `i = ``0``; i < Col; i++) { ` `            ``if` `(M[``0``][i] == ``0``) { ` `                ``DFS(``0``, i, M); ` `            ``} ` `        ``} ` `        ``for` `(``int` `i = ``0``; i < Col; i++) { ` `            ``if` `(M[Row - ``1``][i] == ``0``) { ` `                ``DFS(Row - ``1``, i, M); ` `            ``} ` `        ``} ` `        ``for` `(``int` `i = ``0``; i < Row; i++) { ` `            ``if` `(M[i][``0``] == ``0``) { ` `                ``DFS(i, ``0``, M); ` `            ``} ` `        ``} ` `        ``for` `(``int` `i = ``0``; i < Row; i++) { ` `            ``if` `(M[i][Col - ``1``] == ``0``) { ` `                ``DFS(i, Col - ``1``, M); ` `            ``} ` `        ``} ` ` `  `        ``// count all zeros which are surrounded by 1 ` `        ``int` `result = ``0``; ` `        ``for` `(``int` `i = ``0``; i < Row; i++) { ` `            ``for` `(``int` `j = ``0``; j < Col; j++) { ` `                ``if` `(M[i][j] == ``0``) { ` `                    ``result++; ` `                ``} ` `            ``} ` `        ``} ` `        ``return` `result; ` `    ``} ` ` `  `// driver program to test above function ` `    ``public` `static` `void` `main(String[] args) { ` `        ``int` `M[][] = {{``1``, ``1``, ``1``, ``0``, ``1``}, ` `        ``{``1``, ``0``, ``0``, ``1``, ``0``}, ` `        ``{``1``, ``0``, ``1``, ``0``, ``1``}, ` `        ``{``0``, ``1``, ``1``, ``1``, ``1``}}; ` `        ``System.out.print(CountAllZero(M)); ` `    ``} ` `} ` `// This code is contributed by Rajput-Ji `

## Python3

 `# Python3 program to count number of zeros  ` `# surrounded by 1  ` `Row ``=` `4` `Col ``=` `5` `r ``=` `[``0``, ``0``, ``1``, ``-``1` `] ` `c ``=` `[``1``, ``-``1``, ``0``, ``0` `] ` ` `  `def` `isSafe(x, y, M): ` `     `  `    ``if` `(x >``=` `0` `and` `x < Row ``and` `y >``=` `0` `and` `y < Col): ` `        ``if` `M[x][y] ``=``=` `0``: ` `            ``return` `True` `     `  `    ``return` `False` ` `  `# DFS function to mark all reachable cells from  ` `# (x, y)  ` `def` `DFS(x, y, M): ` `     `  `    ``# make it's visited  ` `    ``M[x][y] ``=` `1` `    ``for` `k ``in` `range``(``4``): ` `        ``if` `(isSafe(x ``+` `r[k], y ``+` `c[k], M)): ` `            ``DFS(x ``+` `r[k], y ``+` `c[k], M)  ` ` `  `# function return count of 0's which are surrounded by 1  ` `def` `CountAllZero(M): ` ` `  `    ``# first we remove all zeros which are not  ` `    ``# surrounded by 1 that means we only remove  ` `    ``# those zeros which are reachable from  ` `    ``# any boundary of given matrix.  ` `    ``for` `i ``in` `range``(Col): ` `        ``if` `(M[``0``][i] ``=``=` `0``): ` `            ``DFS(``0``, i, M)  ` `    ``for` `i ``in` `range``(Col): ` `        ``if` `(M[Row ``-` `1``][i] ``=``=` `0``): ` `            ``DFS(Row ``-` `1``, i, M)  ` `    ``for` `i ``in` `range``(Row):  ` `        ``if` `(M[i][``0``] ``=``=` `0``): ` `            ``DFS(i, ``0``, M)  ` `    ``for` `i ``in` `range``(Row):  ` `        ``if` `(M[i][Col ``-` `1``] ``=``=` `0``): ` `            ``DFS(i, Col ``-` `1``, M)  ` `     `  `    ``# count all zeros which are surrounded by 1  ` `    ``result ``=` `0` `    ``for` `i ``in` `range``(Row):  ` `        ``for` `j ``in` `range``(Col): ` `            ``if` `(M[i][j] ``=``=` `0``): ` `                ``result ``+``=` `1` `     `  `    ``return` `result  ` ` `  `# Driver code  ` `M ``=` `[[``1``, ``1``, ``1``, ``0``, ``1``], [``1``, ``0``, ``0``, ``1``, ``0` `],  ` `    ``[``1``, ``0``, ``1``, ``0``, ``1``] , [ ``0``, ``1``, ``1``, ``1``, ``1` `]]  ` `print``(CountAllZero(M)) ` ` `  `# This code is conributed by shubhamsingh10 `

## C#

 `     `  `// C# program to count number of zeros ` `// surrounded by 1 ` `using` `System; ` `public` `class` `GFG { ` `  `  `    ``readonly` `static` `int` `Row = 4; ` `    ``readonly` `static` `int` `Col = 5; ` `    ``static` `int` `[]r = {0, 0, 1, -1}; ` `    ``static` `int` `[]c = {1, -1, 0, 0}; ` `  `  `    ``static` `bool` `isSafe(``int` `x, ``int` `y, ``int` `[,]M) { ` `        ``if` `(x >= 0 && x = 0 ` `                ``&& y < Col && M[x,y] == 0) { ` `            ``return` `true``; ` `        ``} ` `        ``return` `false``; ` `    ``} ` `  `  `// DFS function to mark all reachable cells from ` `// (x, y) ` `    ``static` `void` `DFS(``int` `x, ``int` `y, ``int` `[,]M) { ` `        ``// make it's visited ` `        ``M[x,y] = 1; ` `        ``for` `(``int` `k = 0; k < 4; k++) { ` `            ``if` `(isSafe(x + r[k], y + c[k], M)) { ` `                ``DFS(x + r[k], y + c[k], M); ` `            ``} ` `        ``} ` `    ``} ` `  `  `// function return count of 0's which are surrounded by 1 ` `    ``static` `int` `CountAllZero(``int` `[,]M) { ` `        ``// first we remove all zeros which are not ` `        ``// surrounded by 1 that means we only remove  ` `        ``// those zeros which are reachable from ` `        ``// any boundary of given matrix. ` `        ``for` `(``int` `i = 0; i < Col; i++) { ` `            ``if` `(M[0,i] == 0) { ` `                ``DFS(0, i, M); ` `            ``} ` `        ``} ` `        ``for` `(``int` `i = 0; i < Col; i++) { ` `            ``if` `(M[Row - 1,i] == 0) { ` `                ``DFS(Row - 1, i, M); ` `            ``} ` `        ``} ` `        ``for` `(``int` `i = 0; i < Row; i++) { ` `            ``if` `(M[i,0] == 0) { ` `                ``DFS(i, 0, M); ` `            ``} ` `        ``} ` `        ``for` `(``int` `i = 0; i < Row; i++) { ` `            ``if` `(M[i,Col - 1] == 0) { ` `                ``DFS(i, Col - 1, M); ` `            ``} ` `        ``} ` `  `  `        ``// count all zeros which are surrounded by 1 ` `        ``int` `result = 0; ` `        ``for` `(``int` `i = 0; i < Row; i++) { ` `            ``for` `(``int` `j = 0; j < Col; j++) { ` `                ``if` `(M[i,j] == 0) { ` `                    ``result++; ` `                ``} ` `            ``} ` `        ``} ` `        ``return` `result; ` `    ``} ` `  `  `// driver program to test above function ` `    ``public` `static` `void` `Main() { ` `        ``int` `[,]M = {{1, 1, 1, 0, 1}, ` `        ``{1, 0, 0, 1, 0}, ` `        ``{1, 0, 1, 0, 1}, ` `        ``{0, 1, 1, 1, 1}}; ` `        ``Console.Write(CountAllZero(M)); ` `    ``} ` `}  ` `// This code is contributed by 29AjayKumar `

Output:

```4
```

Time Complexity: O(Row*Col)

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