Class getGenericSuperclass() method in Java with Examples
Last Updated :
02 Aug, 2021
The getGenericSuperclass() method of java.lang.Class class is used to get the type of the superclass of this entity. This entity can be a class, an array, an interface, etc. The method returns the type of the superclass of this entity.
Syntax:
public Type getGenericSuperclass()
Parameter: This method does not accept any parameter.
Return Value: This method returns the type of the superclass of this entity.
Exceptions: This method throws following exceptions:
- GenericSignatureFormatError: if the generic class signature does not conform to the format specified in The Javaâ„¢ Virtual Machine Specification
- TypeNotPresentException: if the generic superclass refers to a non-existent type declaration
- MalformedParameterizedTypeException: if the generic superclass refers to a parameterized type that cannot be instantiated for any reason
Below programs demonstrate the getGenericSuperclass() method.
Example 1:
Java
public class Test {
public static void main(String[] args)
throws ClassNotFoundException
{
Class myClass = Class.forName( "Test" );
System.out.println(
"Class represented by myClass: "
+ myClass.toString());
System.out.println(
"Type of the superclass of myClass: "
+ myClass.getGenericSuperclass());
}
}
|
Output:
Class represented by myClass: class Test
Type of the superclass of myClass: class java.lang.Object
Example 2:
Java
public class Test {
class Arr {
}
public static void main(String[] args)
throws ClassNotFoundException
{
Class arrClass = Arr. class ;
System.out.println(
"Type of the superclass of arrClass: "
+ arrClass.getGenericSuperclass());
}
}
|
Output:
Type of the superclass of arrClass: class java.lang.Object
Reference: https://docs.oracle.com/javase/9/docs/api/java/lang/Class.html#getGenericSuperclass–
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