Given a binary string of length at-least two. We need to check if it is possible to rearrange a binary string such that there alternate 0’s and 1’s. If possible then output is YES, otherwise output is NO.
Input : 1011
Output : NO
We can’t rearrange the string such that it has alternate 0s and 1s.
Input : 1100
Output : YES
There are exactly two ways to rearrange the string, and they are 0101 or 1010 .
We can place all 0’s in even position and all 1’s in odd position or we can place all 0’s in odd position and all 1’s in even position. If the length of the string is even then to satisfy the given condition the count of 1’s and 0’s must be equal. If the length of the string is odd then to satisfy the given condition the absolute difference of count
of 1’s and 0’s must be one.
Below is the implementation of above approach:
Time Complexity: O(l), where l is length of the binary string.
- Rearrange a binary string as alternate x and y occurrences
- Number of flips to make binary string alternate | Set 1
- Minimum number of characters to be removed to make a binary string alternate
- Python | Check if a given string is binary string or not
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- Check divisibility of binary string by 2^k
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- Check if a binary string contains all permutations of length k
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- Check if a binary string has a 0 between 1s or not | Set 2 (Regular Expression Approach)
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- Rearrange given string to maximize the occurrence of string t
- Rearrange characters in a string such that no two adjacent are same
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