Open In App

Check if array can be converted into strictly decreasing sequence

Improve
Improve
Like Article
Like
Save
Share
Report

Given an array arr[], the task is to check whether given array can be converted into a strictly decreasing sequence with the help of the below operation: 
 

  • Decrease any element(if it is greater than 1) by 1 in one operation

Examples: 
 

Input: arr[] = {11, 11, 11, 11} 
Output : Yes 
Explanation: 
The given sequence can be converted into 
arr[] = {11, 10, 9, 8}
Input: arr[] = {1, 1} 
Output: No 
Explanation: 
The given sequence cannot be converted into strictly decreasing sequence 
 

 

Approach: The idea is to check whether every element of the array is greater than or equal to (N – index of element), because if it is greater than or equal to (N – index of element) that means array can be converted into [N, N-1, N-2, ….1]
Below is the implementation of the above approach: 
 

C++




// C++ implementation to check that
// array can be converted into a
// strictly decreasing sequence
#include <bits/stdc++.h>
using namespace std;
 
// Function to check that array
// can be converted into a
// strictly decreasing sequence
bool check(int* arr, int n)
{
    bool flag = true;
 
    // Loop to check that each element is
    // greater than the (N - index)
    for (int i = 0; i < n; i++) {
 
        // If element is less than (N - index)
        if (arr[i] < n - i) {
            flag = false;
        }
    }
 
    // If array can be converted
    if (flag) {
        return true;
    }
    else {
        return false;
    }
}
 
// Driver Code
int main()
{
    int arr1[] = { 11, 11, 11, 11 };
    int n1 = sizeof(arr1) / sizeof(arr1[0]);
 
    // Function calling
    if (check(arr1, n1)) {
        cout << "Yes" << endl;
    }
    else {
        cout << "No" << endl;
    }
}


Java




// Java implementation to check that
// array can be converted into a
// strictly decreasing sequence
class GFG{
 
// Function to check that array
// can be converted into a
// strictly decreasing sequence
static boolean check(int []arr, int n)
{
    boolean flag = true;
 
    // Loop to check that each element is
    // greater than the (N - index)
    for (int i = 0; i < n; i++)
    {
 
        // If element is less than (N - index)
        if (arr[i] < n - i)
        {
            flag = false;
        }
    }
 
    // If array can be converted
    if (flag)
    {
        return true;
    }
    else
    {
        return false;
    }
}
 
// Driver Code
public static void main(String[] args)
{
    int arr1[] = { 11, 11, 11, 11 };
    int n1 = arr1.length;
 
    // Function calling
    if (check(arr1, n1))
    {
        System.out.print("Yes" + "\n");
    }
    else
    {
        System.out.print("No" + "\n");
    }
}
}
 
// This code is contributed by amal kumar choubey


Python3




# Python3 implementation to check that
# array can be converted into a
# strictly decreasing sequence
 
# Function to check that array
# can be converted into a
# strictly decreasing sequence
def check(arr, n):
 
    flag = True;
 
    # Loop to check that each element
    # is greater than the (N - index)
    for i in range(n):
         
        # If element is less than (N - index)
        if (arr[i] < n - i):
            flag = False;
             
    # If array can be converted
    if (flag):
        return True;
    else:
        return False;
 
# Driver Code
if __name__ == '__main__':
     
    arr1 = [ 11, 11, 11, 11 ];
    n1 = len(arr1);
 
    # Function calling
    if (check(arr1, n1)):
        print("Yes");
    else:
        print("No");
 
# This code is contributed by sapnasingh4991


C#




// C# implementation to check that
// array can be converted into a
// strictly decreasing sequence
using System;
 
class GFG{
 
// Function to check that array
// can be converted into a
// strictly decreasing sequence
static bool check(int []arr, int n)
{
    bool flag = true;
 
    // Loop to check that each element is
    // greater than the (N - index)
    for(int i = 0; i < n; i++)
    {
 
       // If element is less than (N - index)
       if (arr[i] < n - i)
       {
           flag = false;
       }
    }
 
    // If array can be converted
    if (flag)
    {
        return true;
    }
    else
    {
        return false;
    }
}
 
// Driver Code
static public void Main(String[] args)
{
    int []arr1 = { 11, 11, 11, 11 };
    int n1 = arr1.Length;
 
    // Function calling
    if (check(arr1, n1))
    {
        Console.Write("Yes" + "\n");
    }
    else
    {
        Console.Write("No" + "\n");
    }
}
}
 
// This code is contributed by 29AjayKumar


Javascript




<script>
// javascript implementation to check that
// array can be converted into a
// strictly decreasing sequence
 
// Function to check that array
// can be converted into a
// strictly decreasing sequence
function check(arr,n)
{
    var flag = true;
 
    // Loop to check that each element is
    // greater than the (N - index)
    for (let i = 0; i < n; i++) {
 
        // If element is less than (N - index)
        if (arr[i] < n - i) {
            flag = false;
        }
    }
 
    // If array can be converted
    if (flag) {
        return true;
    }
    else {
        return false;
    }
}
 
 
    let arr1= [ 11, 11, 11, 11 ];
    let n1 = arr1.length;
 
    // Function calling
    if (check(arr1, n1)) {
     document.write("Yes");
     }
    else {
        document.write("No");
     }
      
     // This code is contributed by vaibhavrabadiya117.
</script>


Output: 

Yes

 

Time Complexity: O(n)

Auxiliary Space: O(1)



Last Updated : 29 Aug, 2022
Like Article
Save Article
Previous
Next
Share your thoughts in the comments
Similar Reads