# Check if a string contains a palindromic sub-string of even length

S is string containing only lowercase English alphabets. We need to find if there exists at least one palindromic sub-string whose length is even.

Examples:

```Input  : aassss
Output : YES

Input  : gfg
Output : NO
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Notice that a palindrome of even length must contain two same alphabets in the middle. So we just need to check for this condition. If we find two consecutive same alphabets in the string then we output “YES” otherwise “NO”.

Below is the implementation:

## C++

 `// CPP program to check if there is a substring ` `// palindrome of even length. ` `#include ` `using` `namespace` `std; ` ` `  `// function to check if two consecutive same  ` `// characters are present ` `bool` `check(string s) ` `{ ` `    ``for` `(``int` `i = 0; i < s.length() - 1; i++) ` `        ``if` `(s[i] == s[i + 1]) ` `            ``return` `true``; ` `    ``return` `false``; ` `} ` ` `  `int` `main() ` `{ ` `    ``string s = ``"xzyyz"``; ` `    ``if` `(check(s)) ` `        ``cout << ``"YES"` `<< endl; ` `    ``else` `        ``cout << ``"NO"` `<< endl; ` `    ``return` `0; ` `} `

## Java

 `// Java program to check if there is a substring  ` `// palindrome of even length.  ` ` `  `class` `GFG { ` ` `  ` `  `// function to check if two consecutive same  ` `// characters are present  ` `static` `boolean` `check(String s)  ` `{  ` `    ``for` `(``int` `i = ``0``; i < s.length() - ``1``; i++)  ` `        ``if` `(s.charAt(i) == s.charAt(i+``1``))  ` `            ``return` `true``;  ` `    ``return` `false``;  ` `}  ` ` `  `// Driver Code  ` `    ``public` `static` `void` `main(String[] args) { ` ` `  `        ``String s = ``"xzyyz"``;  ` `    ``if` `(check(s))  ` `              ``System.out.println(``"YES"``); ` `    ``else` `        ``System.out.println(``"NO"``); ` `    ``} ` `} `

## Python3

 `# Python 3 program to check if there is  ` `# a substring palindrome of even length. ` ` `  `# function to check if two consecutive ` `# same characters are present ` `def` `check(s): ` ` `  `    ``for` `i ``in` `range` `(``0``, ``len``(s)): ` `        ``if` `(s[i] ``=``=` `s[i ``+` `1``]): ` `            ``return` `True` `             `  `    ``return` `False` ` `  `# Driver Code ` `s ``=` `"xzyyz"` `if``(check(s)): ` `    ``print``(``"YES"``) ` `else``: ` `    ``print``(``"NO"``) ` `     `  `# This code is contributed ` `# by iAyushRAJ `

## C#

 `// C# program to check if there is a substring  ` `// palindrome of even length.  ` `using` `System;  ` `public` `class` `GFG { ` ` `  ` `  `// function to check if two consecutive same  ` `// characters are present  ` `static` `bool` `check(String s)  ` `{  ` `    ``for` `(``int` `i = 0; i < s.Length - 1; i++)  ` `        ``if` `(s[i] == s[i+1])  ` `            ``return` `true``;  ` `    ``return` `false``;  ` `}  ` ` `  `// Driver Code  ` `    ``public` `static` `void` `Main() { ` ` `  `        ``String s = ``"xzyyz"``;  ` `    ``if` `(check(s))  ` `              ``Console.WriteLine(``"YES"``); ` `    ``else` `        ``Console.WriteLine(``"NO"``); ` `    ``} ` `} `

## PHP

 ` `

Output:

```YES
```

My Personal Notes arrow_drop_up Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.

Improved By : jit_t, Rajput-Ji, iAyushRaj