# Check if a string contains a palindromic sub-string of even length

S is string containing only lowercase English alphabets. We need to find if there exists at least one palindromic sub-string whose length is even.

Examples:

Input  : aassss
Output : YES

Input  : gfg
Output : NO

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Notice that a palindrome of even length must contain two same alphabets in the middle. So we just need to check for this condition. If we find two consecutive same alphabets in the string then we output “YES” otherwise “NO”.

Below is the implementation:

## C++

 // CPP program to check if there is a substring // palindrome of even length. #include using namespace std;    // function to check if two consecutive same  // characters are present bool check(string s) {     for (int i = 0; i < s.length() - 1; i++)         if (s[i] == s[i + 1])             return true;     return false; }    int main() {     string s = "xzyyz";     if (check(s))         cout << "YES" << endl;     else         cout << "NO" << endl;     return 0; }

## Java

 // Java program to check if there is a substring  // palindrome of even length.     class GFG {       // function to check if two consecutive same  // characters are present  static boolean check(String s)  {      for (int i = 0; i < s.length() - 1; i++)          if (s.charAt(i) == s.charAt(i+1))              return true;      return false;  }     // Driver Code      public static void main(String[] args) {            String s = "xzyyz";      if (check(s))                System.out.println("YES");     else         System.out.println("NO");     } }

## Python3

 # Python 3 program to check if there is  # a substring palindrome of even length.    # function to check if two consecutive # same characters are present def check(s):        for i in range (0, len(s)):         if (s[i] == s[i + 1]):             return True                    return False    # Driver Code s = "xzyyz" if(check(s)):     print("YES") else:     print("NO")        # This code is contributed # by iAyushRAJ

## C#

 // C# program to check if there is a substring  // palindrome of even length.  using System;  public class GFG {       // function to check if two consecutive same  // characters are present  static bool check(String s)  {      for (int i = 0; i < s.Length - 1; i++)          if (s[i] == s[i+1])              return true;      return false;  }     // Driver Code      public static void Main() {            String s = "xzyyz";      if (check(s))                Console.WriteLine("YES");     else         Console.WriteLine("NO");     } }

## PHP



Output:

YES

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Improved By : jit_t, Rajput-Ji, iAyushRaj