# Check if a string contains two non overlapping sub-strings “geek” and “keeg”

• Last Updated : 21 May, 2021

Given a string str, the task is to check whether the string contains two non-overlapping sub-strings s1 = “geek” and s2 = “keeg” such that s2 starts after s1 ends.
Examples:

Input: str = “geekeekeeg”
Output: Yes
“geek” and “keeg” both are present in the
given string without overlapping.
Input: str = “geekeeg”
Output: No
“geek” and “keeg” both are present but they overlap.

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Approach: Check if the sub-string “geek” occurs before “keeg” in the given string. This problem is simpler when we use a predefined function strstr in order to find the occurrence of a sub-string in the given string.
Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach``#include ``using` `namespace` `std;` `// Function that returns true``// if s contains two non overlapping``// sub strings "geek" and "keeg"``bool` `isValid(``char` `s[])``{``    ``char``* p;` `    ``// If "geek" and "keeg" are both present``    ``// in s without over-lapping and "keeg"``    ``// starts after "geek" ends``    ``if` `((p = ``strstr``(s, ``"geek"``)) && (``strstr``(p + 4, ``"keeg"``)))``        ``return` `true``;` `    ``return` `false``;``}` `// Driver code``int` `main()``{``    ``char` `s[] = ``"geekeekeeg"``;` `    ``if` `(isValid(s))``        ``cout << ``"Yes"``;``    ``else``        ``cout << ``"No"``;` `    ``return` `0;``}`

## Java

 `// Java implementation of the approach``class` `GFG``{` `// Function that returns true``// if s contains two non overlapping``// sub Strings "geek" and "keeg"``static` `boolean` `isValid(String s)``{``    ``// If "geek" and "keeg" are both present``    ``// in s without over-lapping and "keeg"``    ``// starts after "geek" ends``    ``if` `((s.indexOf( ``"geek"``)!=-``1``) &&``        ``(s.indexOf( ``"keeg"``,s.indexOf( ``"geek"``) + ``4``)!=-``1``))``        ``return` `true``;` `    ``return` `false``;``}` `// Driver code``public` `static` `void` `main(String args[])``{``    ``String s = ``"geekeekeeg"``;` `    ``if` `(isValid(s))``        ``System.out.println(``"Yes"``);``    ``else``        ``System.out.println(``"No"``);``}``}` `// This code is contributed by Arnab Kundu`

## Python3

 `# Python 3 implementation of the approach` `# Function that returns true``# if s contains two non overlapping``# sub strings "geek" and "keeg"``def` `isValid(s):``    ``p``=``""` `    ``# If "geek" and "keeg" are both present``    ``# in s without over-lapping and "keeg"``    ``# starts after "geek" ends``    ``p``=``s.find(``"geek"``)``    ``if` `(s.find(``"keeg"``,p``+``4``)):``        ``return` `True` `    ``return` `False` `# Driver code``if` `__name__ ``=``=` `"__main__"``:``    ``s ``=` `"geekeekeeg"` `    ``if` `(isValid(s)):``        ``print``(``"Yes"``)``    ``else``:``        ``print``(``"No"``)` `# This code is contributed by ChitraNayal`

## C#

 `// C# implementation of the approach` `using` `System;` `class` `GFG``{` `// Function that returns true``// if s contains two non overlapping``// sub Strings "geek" and "keeg"``static` `bool` `isValid(``string` `s)``{``    ``// If "geek" and "keeg" are both present``    ``// in s without over-lapping and "keeg"``    ``// starts after "geek" ends``    ``if` `((s.IndexOf( ``"geek"``)!=-1) &&``        ``(s.IndexOf( ``"keeg"``,s.IndexOf( ``"geek"``) + 4)!=-1))``        ``return` `true``;` `    ``return` `false``;``}` `// Driver code``public` `static` `void` `Main()``{``    ``string` `s = ``"geekeekeeg"``;` `    ``if` `(isValid(s))``        ``Console.WriteLine(``"Yes"``);``    ``else``        ``Console.WriteLine(``"No"``);``}``}` `// This code is contributed by AnkitRai01`

## Javascript

 ``
Output:
`Yes`

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