Check if a destination is reachable from source with two movements allowed
Given coordinates of a source point (x1, y1) determine if it is possible to reach the destination point (x2, y2). From any point (x, y) there only two types of valid movements:
(x, x + y) and (x + y, y). Return a boolean true if it is possible else return false.
Note: All coordinates are positive.
Asked in: Expedia, Telstra
Examples:
Input : (x1, y1) = (2, 10)
(x2, y2) = (26, 12)
Output : True
(2, 10)->(2, 12)->(14, 12)->(26, 12)
is a valid path.
Input : (x1, y1) = (20, 10)
(x2, y2) = (6, 12)
Output : False
No such path is possible because x1 > x2
and coordinates are positive
The problem can be solved using simple recursion. Base case would be to check if current x or y coordinate is greater than that of destination, in which case we return false. If it is not the destination point yet we make two calls for both valid movements from that point.
If any of them yields a path we return true else return false.
C++
// C++ program to check if a destination is reachable// from source with two movements allowed#include <bits/stdc++.h>using namespace std;bool isReachable(int sx, int sy, int dx, int dy){ // base case if (sx > dx || sy > dy) return false; // current point is equal to destination if (sx == dx && sy == dy) return true; // check for other 2 possibilities return (isReachable(sx + sy, sy, dx, dy) || isReachable(sx, sy + sx, dx, dy));}// Driver codeint main(){ int source_x = 2, source_y = 10; int dest_x = 26, dest_y = 12; if (isReachable(source_x, source_y, dest_x, dest_y)) cout << "True\n"; else cout << "False\n"; return 0;} |
Java
// Java program to check if a destination is// reachable from source with two movements// allowedclass GFG { static boolean isReachable(int sx, int sy, int dx, int dy) { // base case if (sx > dx || sy > dy) return false; // current point is equal to destination if (sx == dx && sy == dy) return true; // check for other 2 possibilities return (isReachable(sx + sy, sy, dx, dy) || isReachable(sx, sy + sx, dx, dy)); } //driver code public static void main(String arg[]) { int source_x = 2, source_y = 10; int dest_x = 26, dest_y = 12; if (isReachable(source_x, source_y, dest_x, dest_y)) System.out.print("True\n"); else System.out.print("False\n"); }}// This code is contributed by Anant Agarwal. |
Python3
# Python3 program to check if# a destination is reachable# from source with two movements alloweddef isReachable(sx, sy, dx, dy): # base case if (sx > dx or sy > dy): return False # current point is equal to destination if (sx == dx and sy == dy): return True # check for other 2 possibilities return (isReachable(sx + sy, sy, dx, dy) or isReachable(sx, sy + sx, dx, dy))# Driver codesource_x, source_y = 2, 10dest_x, dest_y = 26, 12if (isReachable(source_x, source_y, dest_x, dest_y)): print("True")else: print("False") # This code is contributed by Anant Agarwal. |
C#
// C# program to check if a destination is// reachable from source with two movements// allowedusing System;class GFG { static bool isReachable(int sx, int sy, int dx, int dy) { // base case if (sx > dx || sy > dy) return false; // current point is equal to destination if (sx == dx && sy == dy) return true; // check for other 2 possibilities return (isReachable(sx + sy, sy, dx, dy) || isReachable(sx, sy + sx, dx, dy)); } //driver code public static void Main() { int source_x = 2, source_y = 10; int dest_x = 26, dest_y = 12; if (isReachable(source_x, source_y, dest_x, dest_y)) Console.Write("True\n"); else Console.Write("False\n"); }}// This code is contributed by Anant Agarwal. |
PHP
<?php// PHP program to check if a// destination is reachable// from source with two movements// allowedfunction isReachable($sx, $sy, $dx, $dy){ // base case if ($sx > $dx || $sy > $dy) return false; // current point is equal // to destination if ($sx == $dx && $sy == $dy) return true; // check for other 2 possibilities return (isReachable($sx + $sy, $sy, $dx, $dy) || isReachable($sx, $sy + $sx, $dx, $dy));} // Driver code $source_x = 2; $source_y = 10; $dest_x = 26; $dest_y = 12; if (isReachable($source_x, $source_y, $dest_x, $dest_y)) echo "True\n"; else echo "False\n"; // This code is contributed by Sam007?> |
Javascript
<script>// Javascript program to check if a destination is// reachable from source with two movements// allowed function isReachable(sx, sy, dx, dy) { // base case if (sx > dx || sy > dy) return false; // current polet is equal to destination if (sx == dx && sy == dy) return true; // check for other 2 possibilities return (isReachable(sx + sy, sy, dx, dy) || isReachable(sx, sy + sx, dx, dy)); }// driver program let source_x = 2, source_y = 10; let dest_x = 26, dest_y = 12; if (isReachable(source_x, source_y, dest_x, dest_y)) document.write("True\n"); else document.write("False\n"); </script> |
Output:
True
This article is contributed by Aditi Sharma. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready. To complete your preparation from learning a language to DS Algo and many more, please refer Complete Interview Preparation Course.
In case you wish to attend live classes with experts, please refer DSA Live Classes for Working Professionals and Competitive Programming Live for Students.
