Check if a destination is reachable from source with two movements allowed
Given coordinates of a source point (x1, y1) determine if it is possible to reach the destination point (x2, y2). From any point (x, y) there only two types of valid movements:
(x, x + y) and (x + y, y). Return a boolean true if it is possible else return false.
Note: All coordinates are positive.
Asked in: Expedia, Telstra
Examples:
Input : (x1, y1) = (2, 10)
(x2, y2) = (26, 12)
Output : True
(2, 10)->(2, 12)->(14, 12)->(26, 12)
is a valid path.
Input : (x1, y1) = (20, 10)
(x2, y2) = (6, 12)
Output : False
No such path is possible because x1 > x2
and coordinates are positive
The problem can be solved using simple recursion. Base case would be to check if current x or y coordinate is greater than that of destination, in which case we return false. If it is not the destination point yet we make two calls for both valid movements from that point.
If any of them yields a path we return true else return false.
C++
// C++ program to check if a destination is reachable // from source with two movements allowed #include <bits/stdc++.h> using namespace std; bool isReachable(int sx, int sy, int dx, int dy) { // base case if (sx > dx || sy > dy) return false; // current point is equal to destination if (sx == dx && sy == dy) return true; // check for other 2 possibilities return (isReachable(sx + sy, sy, dx, dy) || isReachable(sx, sy + sx, dx, dy)); } // Driver code int main() { int source_x = 2, source_y = 10; int dest_x = 26, dest_y = 12; if (isReachable(source_x, source_y, dest_x, dest_y)) cout << "True\n"; else cout << "False\n"; return 0; } |
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Java
// Java program to check if a destination is // reachable from source with two movements // allowed class GFG { static boolean isReachable(int sx, int sy, int dx, int dy) { // base case if (sx > dx || sy > dy) return false; // current point is equal to destination if (sx == dx && sy == dy) return true; // check for other 2 possibilities return (isReachable(sx + sy, sy, dx, dy) || isReachable(sx, sy + sx, dx, dy)); } //driver code public static void main(String arg[]) { int source_x = 2, source_y = 10; int dest_x = 26, dest_y = 12; if (isReachable(source_x, source_y, dest_x, dest_y)) System.out.print("True\n"); else System.out.print("False\n"); } } // This code is contributed by Anant Agarwal. |
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Python3
# Python3 program to check if # a destination is reachable # from source with two movements allowed def isReachable(sx, sy, dx, dy): # base case if (sx > dx or sy > dy): return False # current point is equal to destination if (sx == dx and sy == dy): return True # check for other 2 possibilities return (isReachable(sx + sy, sy, dx, dy) or isReachable(sx, sy + sx, dx, dy)) # Driver code source_x, source_y = 2, 10dest_x, dest_y = 26, 12if (isReachable(source_x, source_y, dest_x, dest_y)): print("True") else: print("False") # This code is contributed by Anant Agarwal. |
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C#
// C# program to check if a destination is // reachable from source with two movements // allowed using System; class GFG { static bool isReachable(int sx, int sy, int dx, int dy) { // base case if (sx > dx || sy > dy) return false; // current point is equal to destination if (sx == dx && sy == dy) return true; // check for other 2 possibilities return (isReachable(sx + sy, sy, dx, dy) || isReachable(sx, sy + sx, dx, dy)); } //driver code public static void Main() { int source_x = 2, source_y = 10; int dest_x = 26, dest_y = 12; if (isReachable(source_x, source_y, dest_x, dest_y)) Console.Write("True\n"); else Console.Write("False\n"); } } // This code is contributed by Anant Agarwal. |
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PHP
<?php // PHP program to check if a // destination is reachable // from source with two movements // allowed function isReachable($sx, $sy, $dx, $dy) { // base case if ($sx > $dx || $sy > $dy) return false; // current point is equal // to destination if ($sx == $dx && $sy == $dy) return true; // check for other 2 possibilities return (isReachable($sx + $sy, $sy, $dx, $dy) || isReachable($sx, $sy + $sx, $dx, $dy)); } // Driver code $source_x = 2; $source_y = 10; $dest_x = 26; $dest_y = 12; if (isReachable($source_x, $source_y, $dest_x, $dest_y)) echo "True\n"; else echo "False\n"; // This code is contributed by Sam007 ?> |
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Output:
True
This article is contributed by Aditi Sharma. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
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Improved By : Sam007
