Calculate maximum value using ‘+’ or ‘*’ sign between two numbers in a string

Given a string of numbers, the task is to find the maximum value from the string, you can add a ‘+’ or ‘*’ sign between any two numbers.

Examples:

Input : 01231
Output :
((((0 + 1) + 2) * 3) + 1) = 10
In above manner, we get the maximum value i.e. 10

Input : 891
Output :73
As 8*9*1 = 72 and 8*9+1 = 73.So, 73 is maximum.

Recommended: Please solve it on “PRACTICE ” first, before moving on to the solution.

The task is pretty simple as we can get the maximum value on multiplying all values but the point is to handle the case of 0 and 1 i.e. On multiplying with 0 and 1 we get the lower value as compared to on adding with 0 and 1.
So, use ‘*’ sign between any two numbers(except numbers containing 0 and 1) and use ‘+’ if any of the number is 0 and 1.

C++

 // C++ program to find maximum value #include    using namespace std;    // Function to calculate the value int calcMaxValue(string str) {     // Store first character as integer     // in result     int res = str -'0';        // Start traversing the string     for (int i = 1; i < str.length(); i++)     {         // Check if any of the two numbers         // is 0 or 1, If yes then add current         // element         if (str[i] == '0' || str[i] == '1' ||             res < 2 )             res += (str[i]-'0');            // Else multiply         else             res *= (str[i]-'0');     }        // Return maximum value     return res; }    // Drivers code int main() {     string str = "01891";     cout << calcMaxValue(str);     return 0; }

Java

 // Java program to find maximum value    public class GFG  {     // Method to calculate the value     static int calcMaxValue(String str)     {         // Store first character as integer         // in result         int res = str.charAt(0) -'0';                 // Start traversing the string         for (int i = 1; i < str.length(); i++)         {             // Check if any of the two numbers             // is 0 or 1, If yes then add current             // element             if (str.charAt(i) == '0' || str.charAt(i) == '1' ||                 res < 2 )                 res += (str.charAt(i)-'0');                     // Else multiply             else                 res *= (str.charAt(i)-'0');         }                 // Return maximum value         return res;     }            // Driver Method     public static void main(String[] args)     {         String str = "01891";         System.out.println(calcMaxValue(str));     } }

Python3

 # Python program to find maximum value    # Function to calculate the value  def calcMaxValue(str):        # Store first character as integer     # in result     res = ord(str) - 48        # Start traversing the string      for i in range(1, len(str)):                    # Check if any of the two numbers          # is 0 or 1, If yes then add current          # element         if(str[i] == '0' or            str[i] == '1' or res < 2):             res += ord(str[i]) - 48         else:             res *= ord(str[i]) - 48        return res             # Driver code if __name__== "__main__":     str = "01891";     print(calcMaxValue(str));        # This code is contributed by Sairahul Jella

C#

 //C# program to find maximum value using System;    class GFG {            // Method to calculate the value     static int calcMaxValue(String str)     {         // Store first character as integer         // in result         int res = str -'0';                // Start traversing the string         for (int i = 1; i < str.Length; i++)         {             // Check if any of the two numbers             // is 0 or 1, If yes then add current             // element             if (str[i] == '0' ||                  str[i] == '1' || res < 2 )                 res += (str[i] - '0');                    // Else multiply             else                 res *= (str[i] - '0');         }                // Return maximum value         return res;     }            // Driver Code     static public void Main ()     {         String str = "01891";         Console.Write(calcMaxValue(str));     } }    // This code is contributed by jit_t

PHP



Output:

82

Above program consider the case of small inputs i.e. up to which C/C++ can handle the range of maximum value.

This article is contributed by Sahil Chhabra. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

My Personal Notes arrow_drop_up

Article Tags :
Practice Tags :

1

Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.