Matplotlib.pyplot.gci() in Python
Last Updated :
10 May, 2020
Matplotlib is a library in Python and it is numerical – mathematical extension for NumPy library. Pyplot is a state-based interface to a Matplotlib module which provides a MATLAB-like interface. There are various plots which can be used in Pyplot are Line Plot, Contour, Histogram, Scatter, 3D Plot, etc.
matplotlib.pyplot.gci() method
The gci() method in pyplot module of matplotlib library is used to get the current colorable artist.
Syntax: matplotlib.pyplot.gci()
Parameters: This method does not accept any parameters.
Returns: This method returns the current colorable artist.
Below examples illustrate the matplotlib.pyplot.gci() function in matplotlib.pyplot:
Example 1:
import matplotlib.pyplot as plt
import numpy as np
import matplotlib.gridspec as gridspec
from mpl_toolkits.axes_grid1 import make_axes_locatable
plt.close( 'all' )
arr = np.arange( 100 ).reshape(( 10 , 10 ))
fig = plt.figure(figsize = ( 4 , 4 ))
im = plt.imshow(arr,
interpolation = "none" ,
cmap = "plasma" )
divider = make_axes_locatable(plt.gca())
cax = divider.append_axes( "left" ,
"15 %" ,
pad = "30 %" )
plt.colorbar(im, cax = cax)
print ( "The current colorable artist is :" )
print (plt.gci())
fig.suptitle('matplotlib.pyplot.gci() function \
Example\n\n', fontweight = "bold" )
plt.show()
|
Output:
The current colorable artist is :
AxesImage(50, 44;310x308)
Example 2:
import matplotlib.pyplot as plt
from scipy import sin, cos
fig, ax = plt.subplots( 2 , 1 )
x = [ 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 ]
y1 = sin(x)
y2 = cos(x)
plt.sca(ax[ 0 ])
plt.plot(x, y1)
plt.sca(ax[ 1 ])
plt.plot(x, y2)
print ( "The current colorable artist is :" )
print (plt.gci())
fig.suptitle('matplotlib.pyplot.gci() function \
Example\n\n', fontweight = "bold" )
plt.show()
|
Output:
The current colorable artist is :
None
Share your thoughts in the comments
Please Login to comment...