How to find size of an object in Python?
Last Updated :
17 Jul, 2023
In python, the usage of sys.getsizeof() can be done to find the storage size of a particular object that occupies some space in the memory. This function returns the size of the object in bytes. It takes at most two arguments i.e Object itself.
Note: Only the memory consumption directly attributed to the object is accounted for, not the memory consumption of objects it refers to.
Examples:
Input:
# Any Integer Value
sys.getsizeof(4)
Expected Output: 4 bytes (Size of integer is 4bytes)
Actual Output: 28 bytes
Here’s how we can interpret the actual output. Have a look at the table below:
int
|
28
|
NA
|
str
|
49
|
+1 per additional character (49+total length of characters)
|
tuple
|
40 (Empty Tuple)
|
+8 per additional item in a tuple ( 40 + 8*total length of items )
|
list
|
56 (Empty List)
|
+8 per additional item in a list ( 56 + 8*total length of items )
|
set
|
216
|
0-4 take the size of 216. 5-19 take size 728. 20th will take 2264 and so on…
|
dict
|
232
|
0-5 takes a size of 232. 6-10 size will be 360. 11th will take 640 and so on…
|
func def
|
136
|
No attributes and default arguments
|
Example:
Python3
import sys
a = sys.getsizeof( 12 )
print (a)
b = sys.getsizeof( 'geeks' )
print (b)
c = sys.getsizeof(( 'g' , 'e' , 'e' , 'k' , 's' ))
print (c)
d = sys.getsizeof([ 'g' , 'e' , 'e' , 'k' , 's' ])
print (d)
e = sys.getsizeof({ 1 , 2 , 3 , 4 })
print (e)
f = sys.getsizeof({ 1 : 'a' , 2 : 'b' , 3 : 'c' , 4 : 'd' })
print (f)
|
Output:
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