Given two numbers represented by linked lists, write a function that returns the multiplication of these two linked lists.

Examples:

Input : 9->4->6 8->4 Output : 79464 Input : 3->2->1 1->2 Output : 3852

**Solution**:

Traverse both lists and generate the required numbers to be multiplied and then return the multiplied values of the two numbers.

Algorithm to generate the number from linked list representation:

1) Initialize a variable to zero 2) Start traversing the linked list 3) Add the value of first node to this variable 4) From the second node, multiply the variable by 10 first and then add the value of the node to this variable. 5) Repeat step 4 until we reach the last node of the list.

Use the above algorithm with both of linked lists to generate the numbers.

Below is the complete C program for multiplying two numbers represented as linked lists:

// C program to Multiply two numbers // represented as linked lists #include<stdio.h> #include<stdlib.h> // Linked list node struct node { int data; struct node* next; }; // Function to create a new node // with given data struct node *newNode(int data) { struct node *new_node = (struct node *) malloc(sizeof(struct node)); new_node->data = data; new_node->next = NULL; return new_node; } // Function to insert a node at the // beginning of the Linked List void push(struct node** head_ref, int new_data) { // allocate node struct node* new_node = newNode(new_data); // link the old list off the new node new_node->next = (*head_ref); // move the head to point to the new node (*head_ref) = new_node; } // Multiply contents of two linked lists long multiplyTwoLists (struct node* first, struct node* second) { int num1 = 0, num2 = 0; // Generate numbers from linked lists while (first || second) { if (first) { num1 = num1*10 + first->data; first = first->next; } if (second) { num2 = num2*10 + second->data; second = second->next; } } // Return multiplication of // two numbers return num1*num2; } // A utility function to print a linked list void printList(struct node *node) { while(node != NULL) { printf("%d", node->data); if(node->next) printf("->"); node = node->next; } printf("\n"); } // Driver program to test above function int main(void) { struct node* first = NULL; struct node* second = NULL; // create first list 9->4->6 push(&first, 6); push(&first, 4); push(&first, 9); printf("First List is: "); printList(first); // create second list 8->4 push(&second, 4); push(&second, 8); printf("Second List is: "); printList(second); // Multiply the two lists and see result printf("Result is: "); printf("%ld", multiplyTwoLists(first, second)); return 0; }

Output:

First List is: 9->4->6 Second List is: 8->4 Result is: 79464

### Asked in: Amazon

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