strrchr() function in C/C++

The strrchr() function in C/C++ locates the last occurrence of a character in a string. It returns a pointer to the last occurrence in the string. The terminating null character is considered part of the C string. Therefore, it can also be located to retrieve a pointer to the end of a string. It is defined in cstring header file.
Syntax :

const char* strrchr( const char* str, int ch )
            or
char* strrchr( char* str, int ch )

Parameter :The function takes two mandatory parameters which are described below:

str : specifies the pointer to the null terminated string to be searched for.
ch: specifies the character to be search for.

Return Value: The function returns a pointer to the last location of ch in string, if the ch is found. If not found, it returns a null pointer.

Below programs illustrate the above function:

Program 1:

// C++ program to illustrate 
// the strrchr() function 
#include <bits/stdc++.h> 
using namespace std; 
  
int main() 
{ 
    // Storing it in string array 
    char string[] = "Geeks for Geeks"; 
  
    // The character we've to search for 
    char character = 'k'; 
  
    // Storing in a pointer ptr 
    char* ptr = strrchr(string, character); 
  
    // ptr-string gives the index location 
    if (ptr) 
        cout << "Last position of " << character 
             << " in " << string << " is " << ptr - string; 
  
    // If the character we're searching is not present in the array 
    else
        cout << character << " is not present "
             << string << endl; 
    return 0; 
} 

Output:

Last position of k in Geeks for Geeks is 13

Program 2:

// C++ program to illustrate  
// the strrchr() function 
#include <bits/stdc++.h> 
using namespace std; 
  
int main() 
{ 
    // Storing it in string array 
    char string[] = "Geeks for Geeks"; 
    char* ptr; 
  
    // The character we've to search for 
    char character = 'z'; 
  
    // Storing in a pointer ptr 
    ptr = strrchr(string, character); 
  
    // ptr-string gives the index location 
    if (ptr) 
        cout << "Last position of " << character 
             << " in " << string << " is " << ptr - string; 
  
    // If the character we're searching 
    // is not present in the array 
    else
        cout << character << " is not present in "
             << string << endl; 
    return 0; 
} 

Output:

z is not present in Geeks for Geeks

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