Open In App
Related Articles

Replace two consecutive equal values with one greater

Improve
Improve
Improve
Like Article
Like
Save Article
Save
Report issue
Report

You are given an array of size ‘n’. You have to replace every pair of consecutive values ‘x’ by a single value ‘x+1’ every time until there is no such repetition left and then print the new array.

Example:

Input : 5, 2, 1, 1, 2, 2 
Output : 5 4 
Explanation: 

  • step 1: While traversing, encountered pair of 1(gets replaced by 2. We get 5, 2, 2, 2, 2 
  • step 2: The first encountered pair of 2 gets replaced by 3. We get 5, 3, 2, 2 
  • step 3: Again pair of 2 gets replaced by 3. We get 5, 3, 3 
  • step 4: Recently formed pair of 3 gets replaced by 4. We get 5, 4 

This is our required answer.

Input : 4, 5, 11, 2, 5, 7, 2 
Output : 4 5 11 2 5 7 2

Approach : In this problem you have to traverse the array of integers and check if any two consecutive integers are of a same value X. Then you have to replace that pair of integers with a single integer X+1. After that you have to begin with a new step by re-traversing the array and performing the same operation. 

Implementation:

C++

// C++ program to replace two elements with equal
// values with one greater.
#include <bits/stdc++.h>
using namespace std;
 
// Function to replace consecutive equal
// elements
void replace_elements(int arr[], int n)
{
    int pos = 0;  // Index in result
 
    for (int i = 0; i < n; i++) {
        arr[pos++] = arr[i];
 
        while (pos > 1 && arr[pos - 2] ==
                          arr[pos - 1]) {
            pos--;
            arr[pos - 1]++;
        }
    }
 
    // to print new array
    for (int i = 0; i < pos; i++)
        cout << arr[i] << " ";
}
 
// Driver Code
int main()
{
    int arr[] = { 6, 4, 3, 4, 3, 3, 5 };
    int n = sizeof(arr) / sizeof(int);
    replace_elements(arr, n);
    return 0;
}

                    

Java

// java program to replace two elements
// with equal values with one greater.
public class GFG {
     
    // Function to replace consecutive equal
    // elements
    static void replace_elements(int arr[], int n)
    {
        int pos = 0; // Index in result
     
        for (int i = 0; i < n; i++) {
            arr[pos++] = arr[i];
     
            while (pos > 1 && arr[pos - 2] ==
                                  arr[pos - 1])
            {
                pos--;
                arr[pos - 1]++;
            }
        }
     
        // to print new array
        for (int i = 0; i < pos; i++)
            System.out.print( arr[i] + " ");
    }
     
    // Driver code
    public static void main(String args[])
    {
        int arr[] = { 6, 4, 3, 4, 3, 3, 5 };
        int n = arr.length;
        replace_elements(arr, n);
    }
}
 
// This code is contributed by Sam007

                    

Python3

# python program to replace two elements
# with equal values with one greater.
from __future__ import print_function
 
# Function to replace consecutive equal
# elements
def replace_elements(arr, n):
 
    pos = 0 # Index in result
 
    for i in range(0, n):
        arr[pos] = arr[i]
        pos = pos + 1
        while (pos > 1 and arr[pos - 2]
                        == arr[pos - 1]):
            pos -= 1
            arr[pos - 1] += 1
         
    # to print new array
    for i in range(0, pos):
        print(arr[i], end=" ")
 
# Driver Code
arr = [ 6, 4, 3, 4, 3, 3, 5 ]
n = len(arr)
replace_elements(arr, n)
     
# This code is contributed by Sam007

                    

C#

// C# program to replace two elements
// with equal values with one greater.
using System;
 
class GFG {
     
    // Function to replace consecutive equal
    // elements
    static void replace_elements(int []arr, int n)
    {
        int pos = 0; // Index in result
      
        for (int i = 0; i < n; i++) {
            arr[pos++] = arr[i];
      
            while (pos > 1 && arr[pos - 2] ==
                                  arr[pos - 1])
            {
                pos--;
                arr[pos - 1]++;
            }
        }
      
        // to print new array
        for (int i = 0; i < pos; i++)
            Console.Write( arr[i] + " ");
    }
 
    // Driver code
    static void Main()
    {
        int []arr = { 6, 4, 3, 4, 3, 3, 5 };
        int n = arr.Length;
        replace_elements(arr, n);
    }
}
 
// This code is contributed by Sam007

                    

PHP

<?php
// PHP program to replace two
// elements with equal
// values with one greater.
 
// Function to replace consecutive
// equal elements
function replace_elements($arr,$n)
{
    // Index in result
    $pos = 0;
 
    for ($i = 0; $i < $n; $i++)
    {
        $arr[$pos++] = $arr[$i];
 
        while ($pos > 1 && $arr[$pos - 2] ==
                        $arr[$pos - 1])
        {
            $pos--;
            $arr[$pos - 1]++;
        }
    }
 
    // to print new array
    for ($i = 0; $i < $pos; $i++)
        echo $arr[$i] . " ";
}
 
    // Driver Code
    $arr = array(6, 4, 3, 4, 3, 3, 5);
    $n = count($arr);
    replace_elements($arr, $n);
 
// This code is contributed by Sam007.
?>

                    

Javascript

<script>
 
// JavaScript program to replace two elements with equal
// values with one greater.
 
// Function to replace consecutive equal
// elements
function replace_elements(arr, n) {
    let pos = 0; // Index in result
 
    for (let i = 0; i < n; i++) {
        arr[pos++] = arr[i];
 
        while (pos > 1 && arr[pos - 2] ==
            arr[pos - 1]) {
            pos--;
            arr[pos - 1]++;
        }
    }
 
    // to print new array
    for (let i = 0; i < pos; i++)
        document.write(arr[i] + " ");
}
 
// Driver Code
 
let arr = [6, 4, 3, 4, 3, 3, 5];
let n = arr.length
replace_elements(arr, n);
 
</script>

                    

Output
6 4 3 6 

Complexity Analysis:

  • Time Complexity: O(N2)
  • Auxiliary Space: O(1)


Last Updated : 17 Aug, 2022
Like Article
Save Article
Previous
Next
Share your thoughts in the comments
Similar Reads