Replace all occurrences of pi with 3.14 in a given string

Given a string, the task is to replace all occurrences of pi with 3.14 in the given string.

Examples:

Input : str = "2 * pi + 3 * pi = 5 * pi"
Output : 2 * 3.14 + 3 * 3.14 = 5 * 3.14

Input : str = "pippppiiiipi"
Output : 3.14ppp3.14iii3.14

Input : str = "xpix"
Output : x3.14x



Approach 1:

  1. Create an empty output string.
  2. Traverse the string from the 0th index till second last index since length of pi is 2.
  3. If the alphabets at the current and (current+1)th index form the word “pi”, append “3.14” to the output string.
  4. Else append the alphabet at the current index.

Below is the implementation of the above approach:

C++

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// C++ program to replace all
// pi in a given string with 3.14
  
#include <bits/stdc++.h>
using namespace std;
  
// Function to replace all occurrences
// of pi in a given with 3.14
string replacePi(string input)
{
    string output;
  
    int size = input.length();
  
    // Iterate through second last
    // element of the string
    for (int i = 0; i < size; ++i) {
  
        // If current and current +1 alphabets
        // form the word 'pi'
        // append 3.14 to output
        if (i + 1 < size and input[i] == 'p' and input[i + 1] == 'i') {
            output += "3.14";
            i++;
        }
  
        // Append the current letter
        else {
            output += input[i];
        }
    }
  
    // Return the output string
    return output;
}
  
// Driver Code
int main()
{
    string input = "2 * pi + 3 * pi = 5 * pi";
    cout << replacePi(input);
    return 0;
}

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Java

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// Java program to replace all
// pi in a given String with 3.14
  
class GFG {
  
    // Function to replace all occurrences
    // of pi in a given with 3.14
    public String replacePi(String input)
    {
        String output = "";
  
        int size = input.length();
  
        // Iterate through second last
        // element of the String
        for (int i = 0; i < size; ++i) {
            // If current and current +1 alphabets
            // form the word 'pi'
            // append 3.14 to output
            if (i + 1 < size && input.charAt(i) == 'p' && input.charAt(i + 1) == 'i') {
                output += "3.14";
                i++;
            }
  
            // Append the current letter
            else {
                output += input.charAt(i);
            }
        }
  
        // Return the output String
        return output;
    }
  
    // Driver Code
    public static void main(String args[])
    {
        GFG g = new GFG();
        String input = "2 * pi + 3 * pi = 5 * pi";
        System.out.println(g.replacePi(input));
    }
}
  
// This code has been contributed by 29AjayKumar

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Python3

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# Python program to replace all 
# pi in a given string with 3.14 
  
# Function to replace all occurrences 
# of pi in a given with 3.14 
def replacePi(input):
    output =""; 
  
    size = len(input); 
  
    # Iterate through second last 
    # element of the string 
    for i in range(size):
  
        # If current and current + 1 alphabets 
        # form the word 'pi' 
        # append 3.14 to output 
        if (i + 1 < size and input[i] == 'p' and 
                            input[i + 1] == 'i'): 
            output += "3.14"
            i+= 1
  
        # Append the current letter 
        else:
            output += input[i]; 
    # Return the output string 
    return output; 
  
# Driver Code 
input = "2 * pi + 3 * pi = 5 * pi"
print(replacePi(input));
  
# This code contributed by PrinciRaj1992 

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C#

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// C# program to replace all
// pi in a given string with 3.14
  
using System;
// Function to replace all occurrences
// of pi in a given with 3.14
class gfg {
    public string replacePi(string input)
    {
        string output = "";
  
        int size = input.Length;
  
        // Iterate through second last
        // element of the string
        for (int i = 0; i < size; ++i) {
            // If current and current +1 alphabets
            // form the word 'pi'
            // append 3.14 to output
            if (i + 1 < size && input[i] == 'p' && input[i + 1] == 'i') {
                output += "3.14";
                i++;
            }
  
            // Append the current letter
            else {
                output += input[i];
            }
        }
  
        // Return the output string
        return output;
    }
}
  
// Driver Code
class geek {
    public static int Main()
    {
        gfg g = new gfg();
        string input = "2 * pi + 3 * pi = 5 * pi";
        Console.WriteLine(g.replacePi(input));
        return 0;
    }
}
// This code is contributed by Soumik

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Output:

2 * 3.14 + 3 * 3.14 = 5 * 3.14

Time Complexity: O(N), where N is the length of the given string.

Approach 2: (In Java)
To replace all the PI occurrences to 3.14, use replaceAll() method of Java String Class.

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public class ReplacePI {
    public static void main(String[] args)
    {
        // Declare a String
        String expression = "2 * pi + 3 * pi = 5 * pi";
  
        // Call replaceAll() method to replace PI to 3.14
        expression = expression.replaceAll("pi", "3.14");
  
        // Print the result
        System.out.println(expression);
    }
}

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Output:

2 * 3.14 + 3 * 3.14 = 5 * 3.14


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