Removing punctuations from a given string

Given a string, remove the punctuation from the string if the given character is a punctuation character, as classified by the current C locale. The default C locale classifies these characters as punctuation: 

! " # $ % & ' ( ) * + , - . / : ; ? @ [ \ ] ^ _ ` { | } ~ 

Examples:

Input : %welcome' to @geeksforgeek<s
Output : welcome to geeksforgeeks

Input : Hello!!!, he said ---and went.
Output : Hello he said and went

Approach: First check the input string if it consists of punctuations then we have to make it punctuation free. In order to do this, we will traverse over the string, and if punctuations are found we will remove them. Let’s say the input string is ‘$Student@‘ then we have to remove $ and @, furthermore we have to print the plain string ‘Student‘ which is free from any punctuations.

Algorithm:

1. Initialize the input string
2. Check if the character present in the string is punctuation or not.
3. If a character is a punctuation, then erase that character and decrement the index.
4. Print the output string, which will be free of any punctuation.

Below is the implementation of the above approach:

C++

// CPP program to remove punctuation from a given string

#include <iostream>
using namespace std;

int main()
{
    // input string
    std::string str = "Welcome???@@##$ to#$% Geeks%$^for$%^&Geeks";

    for (int i = 0, len = str.size(); i < len; i++)
    {
        // check whether parsing character is punctuation or not
        if (ispunct(str[i]))
        {
            str.erase(i--, 1);
            len = str.size();
        }
    }

    // print string without punctuation
    std::cout << str;
    return 0;
}

Java

// Java program to remove punctuation from a given string

public class Test
{
    public static void main(String[] args)
    {
        // input string
        String str = "Welcome???@@##$ to#$% Geeks%$^for$%^&Geeks";

        // similar to Matcher.replaceAll
        str = str.replaceAll("\\p{Punct}","");

        System.out.println(str);
    }

}
// This code is contributed by Gaurav Miglani

Python3

# Python program to remove punctuation from a given string
# Function to remove punctuation
def Punctuation(string):

    # punctuation marks
    punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~'''

    # traverse the given string and if any punctuation
    # marks occur replace it with null
    for x in string.lower():
        if x in punctuations:
            string = string.replace(x, "")

    # Print string without punctuation
    print(string)

# Driver program
string = "Welcome???@@##$ to#$% Geeks%$^for$%^&Geeks"
Punctuation(string)

C#

// C# program to remove punctuation
// from a given string
using System;
using System.Text.RegularExpressions;

class GFG
{
public static void Main()
{
    // input string
    String str = "Welcome???@@##$ to#$% Geeks%$^for$%^&Geeks";

    // similar to Matcher.replaceAll
    str = Regex.Replace(str,@"[^\w\d\s]","");

    Console.Write(str);
}
}

// This code is contributed
// by 29AjayKumar

Javascript

<script>

// JavaScript program to remove punctuation from a given string
    {
        // input string
        var str = "Welcome???@@##$ to#$% Geeks%$^for$%^&Geeks";

        // similar to Matcher.replaceAll
        str = str.replace(/[^a-zA-Z ]/g, "");

        document.write(str);
    }

// This code is contributed by shivanisingh

</script>

Output

Welcome to GeeksforGeeks

Time Complexity: O(n²) 
Auxiliary Space: O(1)

This article is contributed by Aarti_Rathi and Pramod Kumar. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.