Given a string ‘str’, the task is to remove all the characters from the string that have even frequencies.
Input: str = "aabbbddeeecc" Output: bbbeee The characters a, d, c have even frequencies So, they are removed from the string. Input: str = "zzzxxweeerr" Output: zzzweee
- Create a map and store the frequency of each character from the string to the same map.
- Then, traverse the string and find out which characters have even frequencies with the help of the map.
- Ignore all those characters which have even frequencies and store the rest in a new string.
- Finally, display the new string.
Below is the implementation of the above approach:
- String with frequency of characters in Lucas Sequence
- Character whose frequency is equal to the sum of frequencies of other characters of the given string
- Check if a string has all characters with same frequency with one variation allowed
- Check whether frequency of characters in a string makes Fibonacci Sequence
- Number of Positions to partition the string such that atleast m characters with same frequency are present in each substring
- Remove characters from a numeric string such that string becomes divisible by 8
- Remove characters from the first string which are present in the second string
- Remove all characters other than alphabets from string
- Remove all non-alphabetical characters of a String in Java
- Remove characters from string that appears strictly less than K times
- Number of ways to remove a sub-string from S such that all remaining characters are same
- Check if frequency of character in one string is a factor or multiple of frequency of same character in other string
- Program to check if all characters have even frequency
- Check if frequency of all characters can become same by one removal
- Remove elements from the array whose frequency lies in the range [l, r]
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