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Remove all occurrences of a character from a string using STL

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  • Last Updated : 21 Dec, 2021
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Given a string S and a character C, the task is to remove all the occurrences of the character C from the given string.

Examples:

Input:vS = “GFG IS FUN”, C = ‘F’ 
Output:GG IS UN 
Explanation: 
Removing all occurrences of the character ‘F’ modifies S to “GG IS UN”. 
Therefore, the required output is GG IS UN

Input: S = “PLEASE REMOVE THE SPACES”, C = ‘ ‘ 
Output: PLEASEREMOVETHESPACES 
Explanation: 
Removing all occurrences of the character ‘ ‘ modifies S to “GG IS UN”. 
 

Approach: The idea is to use erase() method and remove() function from C++ STL. Below is the syntax to remove all the occurrences of a character from a string.

S.erase(remove(S.begin(), S.end(), c), S.end())

Below is the implementation of the above approach:

C++




// C++ program of the above approach
#include <algorithm>
#include <iostream>
using namespace std;
 
// Function to remove all occurrences
// of C from the string S
string removeCharacters(string S, char c)
{
 
    S.erase(remove(
                S.begin(), S.end(), c),
            S.end());
 
    return S;
}
 
// Driver Code
int main()
{
 
    // Given String
    string S = "GFG is Fun";
    char C = 'F';
    cout << "String Before: " << S << endl;
 
    // Function call
    S = removeCharacters(S, C);
 
    cout << "String After: " << S << endl;
    return 0;
}

Output: 

String Before: GFG is Fun
String After: GG is un

 

Time Complexity: O(N2)
Auxiliary Space: O(1)

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