# Python | Zip Uneven Tuple

In python, zipping is a utility where we pair one record with the other. Usually this task is successful only in the cases when the sizes of both the records to be zipped is of the same size. But sometimes we require that different sized records also to be zipped. Let’s discuss certain ways in which this problem can be solved if it occurs.

Method #1 : Using `enumerate()` + loop
This is the way in which we use the brute force method to achieve this particular task. In this process we loop both the tuple and when one becomes larger than other we cycle the elements to begin them from the beginning.

 `# Python3 code to demonstrate  ` `# Zip Uneven Tuple ` `# using enumerate() + loop ` ` `  `# initializing tuples ` `test_tup1 ``=` `(``7``, ``8``, ``4``, ``5``, ``9``, ``10``) ` `test_tup2 ``=` `(``1``, ``5``, ``6``) ` ` `  `# printing original tuples ` `print` `(``"The original tuple 1 is : "` `+` `str``(test_tup1)) ` `print` `(``"The original tuple 2 is : "` `+` `str``(test_tup2)) ` ` `  `# using enumerate() + loop ` `# Zip Uneven Tuple ` `res ``=` `[] ` `for` `i, j ``in` `enumerate``(test_tup1): ` `    ``res.append((j, test_tup2[i ``%` `len``(test_tup2)])) ` ` `  `# printing result  ` `print` `(``"The zipped tuple is : "` `+` `str``(res)) `

Output :

```The original tuple 1 is : (7, 8, 4, 5, 9, 10)
The original tuple 2 is : (1, 5, 6)
The zipped tuple is : [(7, 1), (8, 5), (4, 6), (5, 1), (9, 5), (10, 6)]
```

Method #2 : Using `itertools.cycle()`
This is yet another way to perform this particular task, in this we cycle the smaller tuple so that it can begin zipping from beginning in case the smaller tuple gets exhausted using a zip function.

 `# Python3 code to demonstrate  ` `# Zip Uneven Tuple ` `# using itertools.cycle() ` `from` `itertools ``import` `cycle ` ` `  `# initializing tuples ` `test_tup1 ``=` `(``7``, ``8``, ``4``, ``5``, ``9``, ``10``) ` `test_tup2 ``=` `(``1``, ``5``, ``6``) ` ` `  `# printing original tuples ` `print` `(``"The original tuple 1 is : "` `+` `str``(test_tup1)) ` `print` `(``"The original tuple 2 is : "` `+` `str``(test_tup2)) ` ` `  `# using itertools.cycle() ` `# Zip Uneven Tuple ` `res ``=` `list``(``zip``(test_tup1, cycle(test_tup2)) ``if` `len``(test_tup1) > ``len``(test_tup2) ``else` `zip``(cycle(test_tup1), test_tup2)) ` ` `  `# printing result  ` `print` `(``"The zipped tuple is : "` `+` `str``(res)) `

Output :

```The original tuple 1 is : (7, 8, 4, 5, 9, 10)
The original tuple 2 is : (1, 5, 6)
The zipped tuple is : [(7, 1), (8, 5), (4, 6), (5, 1), (9, 5), (10, 6)]
```

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