Python – Test if all rows contain any common element with other Matrix

Last Updated : 16 Nov, 2020

Given two Matrices, check if all rows contain at least one element common with the same index row of other Matrix.

Input : test_list1 = [[5, 6, 1], [2, 4], [9, 3, 5]], test_list2 = [[9, 1, 2], [9, 8, 2], [3, 7, 10]]
Output : True
Explanation : 1, 2 and 3 are common elements in rows.
Input : test_list1 = [[5, 6, 1], [2, 4], [9, 2, 6]], test_list2 = [[9, 1, 2], [9, 8, 2], [3, 7, 6]]
Output : True
Explanation : 1, 2 and 6 are common elements in rows.

Method #1 : Using loop + in operator

In this, we iterate each row of matrix, and check for any element matching in other list using in operator, if any element is found, we mark it true, if all rows are true, True is returned.

Python3

# Python3 code to demonstrate working of 
# Test if all rows contain any common element with other Matrix
# Using loop "+" in operator
  
# initializing lists
test_list1 = [[5, 6, 1], [2, 4], [9, 3, 5]]
test_list2 = [[9, 1, 2], [9, 8, 2], [3, 7, 10]]
  
# printing original lists
print("The original list 1 is : " + str(test_list1))
print("The original list 2 is : " + str(test_list2))
  
res = True
for idx in range(0, len(test_list1)):
      
    temp = False
      
    # checking for any common element in 2nd list
    for ele in test_list1[idx]:
        if ele in test_list2[idx]:
            temp = True 
            break 
          
    # if any element not found, Result is false    
    if not temp :
        res = False 
        break
  
# printing result 
print("All row contain commmon elements with other Matrix : " + str(res))

Output:

The original list 1 is : [[5, 6, 1], [2, 4], [9, 3, 5]]
The original list 2 is : [[9, 1, 2], [9, 8, 2], [3, 7, 10]]
All row contain commmon elements with other Matrix : True

Method #2 : Using any() + loop

In this, one nested loop is avoided and the result is computed using any() for getting any common element in the 2nd Matrix.

Python3

# Python3 code to demonstrate working of 
# Test if all rows contain any common element with other Matrix
# Using loop any() "+" loop
  
# initializing lists
test_list1 = [[5, 6, 1], [2, 4], [9, 3, 5]]
test_list2 = [[9, 1, 2], [9, 8, 2], [3, 7, 10]]
  
# printing original lists
print("The original list 1 is : " + str(test_list1))
print("The original list 2 is : " + str(test_list2))
  
res = True
for idx in range(0, len(test_list1)):
      
    # checking for common element in list 2 in same index
    temp = any(ele in test_list2[idx] for ele in test_list1[idx])
          
    # if any element not found, Result is false    
    if not temp :
        res = False 
        break
  
# printing result 
print("All row contain commmon elements with other Matrix : " + str(res))

Output:

The original list 1 is : [[5, 6, 1], [2, 4], [9, 3, 5]]
The original list 2 is : [[9, 1, 2], [9, 8, 2], [3, 7, 10]]
All row contain commmon elements with other Matrix : True

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