# Python | SymPy combinatorics.next_lex() method

With the help of `sympy.combinatorics.partitions.IntegerPartition().next_lex()` method, we can get the next partition of integer n in lexical order by using `sympy.combinatorics.partitions.IntegerPartition().next_lex()` method.

Syntax : `sympy.combinatorics.partitions.IntegerPartition().next_lex()`

Return : Return the lexical value of next partition of integer n.

Example #1 :
In this example we can see that by using `sympy.combinatorics.partitions.IntegerPartition().next_lex()` method, we are able to get the lexical value of next partition of integer n.

 `# import sympy and IntegerPartition ` `from` `sympy.combinatorics.partitions ``import` `IntegerPartition ` `from` `sympy ``import` `*` `   `  `# Using sympy.combinatorics.partitions.IntegerPartition().next_lex() method ` `gfg ``=` `IntegerPartition([``1``, ``2``, ``3``]) ` `   `  `print``(gfg.next_lex()) `

Output :

[3, 3]

Example #2 :

 `# import sympy and IntegerPartition ` `from` `sympy.combinatorics.partitions ``import` `IntegerPartition ` `from` `sympy ``import` `*` `   `  `# Using sympy.combinatorics.partitions.IntegerPartition().next_lex() method ` `gfg ``=` `IntegerPartition([``1``, ``2``, ``3``, ``4``, ``3``, ``2``, ``1``]) ` `   `  `print``(gfg.next_lex()) `

Output :

[4, 3, 3, 2, 2, 2]

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