Python | Split string in groups of n consecutive characters

Given a string (be it either string of numbers or characters), write a Python program to split the string by every nth character.

Examples: 

Input : str = "Geeksforgeeks", n = 3
Output : ['Gee', 'ksf', 'oor', 'gee', 'ks']

Input : str = "1234567891234567", n = 4
Output : [1234, 5678, 9123, 4567]

 
Method #1: Using list comprehension

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# Python code to split string
# by every 3th number
  
# String initialization
string = "Geeksforgeeks"
  
# Defining splitting point
n = 3
  
# Using list comprehension
out = [(string[i:i+n]) for i in range(0, len(string), n)]
  
# Printing output
print(out)

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Output:


['Gee', 'ksf', 'org', 'eek', 's']





 

Method #2: Using zip_longest











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# Python code to split string of number 


# and character into every 4th number 


  


# Importing 


from itertools import zip_longest 


  


# Group function using zip_longest to split 


def group(n, iterable, fillvalue=None): 


    args = [iter(iterable)] * n 


    return zip_longest(fillvalue=fillvalue, *args) 


  


# String initialization 


str = '123GeeksForGeeks4567'


  


# Split point 


n=4


  


# list of seperated string 


out_string = [''.join(lis) for lis in group(n, str, '')] 


  


# Output list initialization 


out_no = [] 


  


# Converting list of string into list of integer 


for a in out_string: 


    out_no.append(a) 


  


# Printing list 


print(out_no) 



















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Output:


['123G', 'eeks', 'ForG', 'eeks', '4567']






          
          
          
          

            

    

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