# Python – Sort dictionaries list by Key’s Value list index

Given list of dictionaries, sort dictionaries on basis of Key’s index value.

Input : [{“Gfg” : [6, 7, 8], “is” : 9, “best” : 10},
{“Gfg” : [2, 0, 3], “is” : 11, “best” : 19},
{“Gfg” : [4, 6, 9], “is” : 16, “best” : 1}], K = “Gfg”, idx = 0
Output : [{‘Gfg’: [2, 0, 3], ‘is’: 11, ‘best’: 19}, {‘Gfg’: [4, 6, 9], ‘is’: 16, ‘best’: 1}, {‘Gfg’: [6, 7, 8], ‘is’: 9, ‘best’: 10}]
Explanation : 2<4<6, hence dictionary ordered in that way by 0th index of Key.

Input : [{“Gfg” : [6, 7, 8], “is” : 9, “best” : 10},
{“Gfg” : [2, 0, 3], “is” : 11, “best” : 19},
{“Gfg” : [4, 6, 9], “is” : 16, “best” : 1}], K = “Gfg”, idx = 1
Output : [{‘Gfg’: [2, 0, 3], ‘is’: 11, ‘best’: 19}, {‘Gfg’: [4, 6, 9], ‘is’: 16, ‘best’: 1}, {‘Gfg’: [6, 7, 8], ‘is’: 9, ‘best’: 10}]
Explanation : 0<6<7, hence dictionary ordered in that way by 1st index.

Method #1 : Using sorted() + lambda

The combination of above functions can be used to solve this problem. In this, we perform sort using sorted and logic based on list index is provided in lambda function.

## Python3

 `# Python3 code to demonstrate working of  ` `# Sort dictionaries list by Key's Value list index ` `# Using sorted() + lambda ` ` `  `# initializing lists ` `test_list ``=` `[{``"Gfg"` `: [``6``, ``7``, ``8``], ``"is"` `: ``9``, ``"best"` `: ``10``},  ` `             ``{``"Gfg"` `: [``2``, ``0``, ``3``], ``"is"` `: ``11``, ``"best"` `: ``19``}, ` `             ``{``"Gfg"` `: [``4``, ``6``, ``9``], ``"is"` `: ``16``, ``"best"` `: ``1``}] ` ` `  `# printing original list ` `print``(``"The original list : "` `+` `str``(test_list)) ` ` `  `# initializing K  ` `K ``=` `"Gfg"` ` `  `# initializing idx  ` `idx ``=` `2` ` `  `# using sorted() to perform sort in basis of 1 parameter key and  ` `# index ` `res ``=` `sorted``(test_list, key ``=` `lambda` `ele: ele[K][idx]) ` `     `  `# printing result  ` `print``(``"The required sort order : "` `+` `str``(res)) `

Output

The original list : [{‘Gfg’: [6, 7, 8], ‘is’: 9, ‘best’: 10}, {‘Gfg’: [2, 0, 3], ‘is’: 11, ‘best’: 19}, {‘Gfg’: [4, 6, 9], ‘is’: 16, ‘best’: 1}]
The required sort order : [{‘Gfg’: [2, 0, 3], ‘is’: 11, ‘best’: 19}, {‘Gfg’: [6, 7, 8], ‘is’: 9, ‘best’: 10}, {‘Gfg’: [4, 6, 9], ‘is’: 16, ‘best’: 1}]

Method #2 : Using sorted() + lambda (Additional parameter in case of tie)

This is modification in sorting of values, adding another parameter in case of tie of values among list.

## Python3

 `# Python3 code to demonstrate working of  ` `# Sort dictionaries list by Key's Value list index ` `# Using sorted() + lambda (Additional parameter in case of tie) ` ` `  `# initializing lists ` `test_list ``=` `[{``"Gfg"` `: [``6``, ``7``, ``9``], ``"is"` `: ``9``, ``"best"` `: ``10``},  ` `             ``{``"Gfg"` `: [``2``, ``0``, ``3``], ``"is"` `: ``11``, ``"best"` `: ``19``}, ` `             ``{``"Gfg"` `: [``4``, ``6``, ``9``], ``"is"` `: ``16``, ``"best"` `: ``1``}] ` ` `  `# printing original list ` `print``(``"The original list : "` `+` `str``(test_list)) ` ` `  `# initializing K  ` `K ``=` `"Gfg"` ` `  `# initializing idx  ` `idx ``=` `2` ` `  `# initializing K2  ` `K2 ``=` `"best"` ` `  `# using sorted() to perform sort in basis of 2 parameter key ` `# inner is evaluated after the outer key in lambda order ` `res ``=` `sorted``(``sorted``(test_list, key ``=` `lambda` `ele: ele[K2]), key ``=` `lambda` `ele: ele[K][idx]) ` `     `  `# printing result  ` `print``(``"The required sort order : "` `+` `str``(res)) `

Output

The original list : [{‘Gfg’: [6, 7, 9], ‘is’: 9, ‘best’: 10}, {‘Gfg’: [2, 0, 3], ‘is’: 11, ‘best’: 19}, {‘Gfg’: [4, 6, 9], ‘is’: 16, ‘best’: 1}]
The required sort order : [{‘Gfg’: [2, 0, 3], ‘is’: 11, ‘best’: 19}, {‘Gfg’: [4, 6, 9], ‘is’: 16, ‘best’: 1}, {‘Gfg’: [6, 7, 9], ‘is’: 9, ‘best’: 10}]

My Personal Notes arrow_drop_up Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.

Article Tags :

Be the First to upvote.

Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.