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Python – Similar other index element of K
• Last Updated : 28 Jul, 2020

Given List of elements, other list and K, extract all the similar other list index elements if element is K in List.

Input  :  test_list = [6, 4, 6, 3, 6], arg_list = [7, 5, 4, 6, 3], K = 6

Output : [7, 4, 3]

Explanation :  7, 4 and 3 correspond to occurrences of 6 in first list.

Input  :  test_list = [2, 3], arg_list = [4, 6], K = 3

Output : 

Explanation :  6 corresponds to only occurrence of 3.

Method #1 : Using enumerate() + list comprehension

The combination of above methods provide a way in which this task can be solved. In this, we check for like index from other list using enumerate() and create new list using list comprehension.

## Python3

 `# Python3 code to demonstrate working of``# Similar other index element if K``# Using list comprehension + enumerate()`` ` `# initializing list``test_list ``=` `[``5``, ``7``, ``3``, ``2``, ``3``, ``8``, ``6``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# initializing arg. list``arg_list ``=` `[``4``, ``5``, ``8``, ``3``, ``7``, ``9``, ``3``]`` ` `# initializing K``K ``=` `3`` ` `# Using enumerate() to locate similar index in other list and extract element``res ``=` `[ele ``for` `idx, ele ``in` `enumerate``(arg_list) ``if` `test_list[idx] ``=``=` `K]`` ` `# printing result``print``(``"Extracted elements : "` `+` `str``(res))`
Output
```The original list : [5, 7, 3, 2, 3, 8, 6]
Extracted elements : [8, 7]

```

Method #2 : Using list comprehension + zip()

The combination of above functions can be used to solve this problem. In this, we performing combining each element with other among both lists using zip().

## Python3

 `# Python3 code to demonstrate working of``# Similar other index element if K``# Using list comprehension + zip()`` ` `# initializing list``test_list ``=` `[``5``, ``7``, ``3``, ``2``, ``3``, ``8``, ``6``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# initializing arg. list``arg_list ``=` `[``4``, ``5``, ``8``, ``3``, ``7``, ``9``, ``3``]`` ` `# initializing K``K ``=` `3`` ` `# Using zip() to lock both the lists, with similar indices mapping``res ``=` `[ele ``for` `ele, ele1 ``in` `zip``(arg_list, test_list) ``if` `ele1 ``=``=` `K]`` ` `# printing result``print``(``"Extracted elements : "` `+` `str``(res))`
Output
```The original list : [5, 7, 3, 2, 3, 8, 6]
Extracted elements : [8, 7]

```

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