Python Set | pop()
This in-built function of Python helps to pop out elements from a set just like the principal used in the concept while implementing Stack. This method removes a random element from the set and returns the removed element. Unlike, a stack a random element is popped off the set.
Syntax:
# Pops a random element from S # and returns it. S.pop()
This is one of the basic functions of the set and accepts no arguments. The return value is the popped element from the set. Once the element is popped out of the set, the set loses the element and it is updated to a set without the element.
Examples:
Input :
sets = {1, 2, 3, 4, 5}
Output :
1
Updated set is {2, 3, 4, 5}
Input :
sets = {"ram", "rahim", "ajay", "rishav", "aakash"}
Output :
rahim
Updated set is {'ram', 'rishav', 'ajay', 'aakash'}
# Python code to illustrate pop() method S = {"ram", "rahim", "ajay", "rishav", "aakash"} # Popping three elements and printing them print(S.pop()) print(S.pop()) print(S.pop()) # The updated set print("Updated set is", S) |
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Output:
rishav
ram
rahim
Updated set is {'aakash', 'ajay'}
On the other hand, if the set is empty, then a TypeError is returned as shown by the following program.
# Python code to illustrate pop() method # on an empty set S = {} # Popping three elements and printing them print(S.pop()) # The updated set print("Updated set is", S) |
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Output:
No Output
Error:
Traceback (most recent call last):
File "/home/7c5b1d5728eb9aa0e63b1d70ee5c410e.py", line 6, in
print(S.pop())
TypeError: pop expected at least 1 arguments, got 0
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