Python – Remove N characters after K
Given a String, remove N characters after K character.
Input : test_str = ‘ge@987eksfor@123geeks is best@212 for cs’, N = 3, K = ‘@’
Output : ‘geeksforgeeks is best for cs’
Explanation : All 3 required occurrences removed.Input : test_str = ‘geeksfor@123geeks is best for cs’, N = 3, K = ‘@’
Output : ‘geeksforgeeks is best for cs’
Explanation : @123 is removed.
Method #1 : Using re.sub()
In this, we specify appropriate regex to capture the element and to remove next N occurrences from String. The sub() is used to perform replacement.
Python3
# Python3 code to demonstrate working of # Remove N characters after K# Using re.sub()import re # initializing stringstest_str = 'geeksfor@123geeks is best@212 for cs' # printing original stringprint("The original string is : " + str(test_str)) # initializing N N = 3 # initializing K K = '@' # using re.sub() to perform task res = re.sub(r'\@...', '', test_str) # printing result print("The String after removal : " + str(res)) |
Output
The original string is : geeksfor@123geeks is best@212 for cs The String after removal : geeksforgeeks is best for cs
Method #2 : Using re.sub() + occurrence option
This is similar to above, just using 4th argument of re.sub() to control the occurrence counts we wish to perform replace.
Python3
# Python3 code to demonstrate working of # Remove N characters after K# Using re.sub() + occurrence optionimport re # initializing stringstest_str = 'geeksfor@123geeks is best@212 for cs' # printing original stringprint("The original string is : " + str(test_str)) # initializing N N = 3 # initializing K K = '@' # using re.sub() to perform task # controlling occurrence using 4th arg.# removes just 1st occurrenceres = re.sub(r'\@...', '', test_str, 1) # printing result print("The String after removal : " + str(res)) |
Output
The original string is : geeksfor@123geeks is best@212 for cs The String after removal : geeksforgeeks is best@212 for cs
