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Python – Remove N characters after K

  • Last Updated : 30 Aug, 2020

Given a String, remove N characters after K character.

Input : test_str = ‘ge@987eksfor@123geeks is best@212 for cs’, N = 3, K = ‘@’
Output : ‘geeksforgeeks is best for cs’
Explanation : All 3 required occurrences removed.

Input : test_str = ‘geeksfor@123geeks is best for cs’, N = 3, K = ‘@’
Output : ‘geeksforgeeks is best for cs’
Explanation : @123 is removed.

Method #1 : Using re.sub()

In this, we specify appropriate regex to capture the element and to remove next N occurrences from String. The sub() is used to perform replacement.

Python3




# Python3 code to demonstrate working of 
# Remove N characters after K
# Using re.sub()
import re
  
# initializing strings
test_str = 'geeksfor@123geeks is best@212 for cs'
  
# printing original string
print("The original string is : " + str(test_str))
  
# initializing N 
N = 3
  
# initializing K 
K = '@'
  
# using re.sub() to perform task 
res = re.sub(r'\@...', '', test_str)
  
# printing result 
print("The String after removal : " + str(res)) 
Output
The original string is : geeksfor@123geeks is best@212 for cs
The String after removal : geeksforgeeks is best for cs

Method #2 : Using re.sub() + occurrence option

This is similar to above, just using 4th argument of re.sub() to control the occurrence counts we wish to perform replace.

Python3




# Python3 code to demonstrate working of 
# Remove N characters after K
# Using re.sub() + occurrence option
import re
  
# initializing strings
test_str = 'geeksfor@123geeks is best@212 for cs'
  
# printing original string
print("The original string is : " + str(test_str))
  
# initializing N 
N = 3
  
# initializing K 
K = '@'
  
# using re.sub() to perform task 
# controlling occurrence using 4th arg.
# removes just 1st occurrence
res = re.sub(r'\@...', '', test_str, 1)
  
# printing result 
print("The String after removal : " + str(res)) 
Output
The original string is : geeksfor@123geeks is best@212 for cs
The String after removal : geeksforgeeks is best@212 for cs


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