Given a String, remove N characters after K character.
Input : test_str = ‘ge@987eksfor@123geeks is best@212 for cs’, N = 3, K = ‘@’
Output : ‘geeksforgeeks is best for cs’
Explanation : All 3 required occurrences removed.Input : test_str = ‘geeksfor@123geeks is best for cs’, N = 3, K = ‘@’
Output : ‘geeksforgeeks is best for cs’
Explanation : @123 is removed.
Method #1 : Using re.sub()
In this, we specify appropriate regex to capture the element and to remove next N occurrences from String. The sub() is used to perform replacement.
Python3
# Python3 code to demonstrate working of # Remove N characters after K # Using re.sub() import re # initializing strings test_str = 'geeksfor@123geeks is best@212 for cs' # printing original string print ( "The original string is : " + str (test_str)) # initializing N N = 3 # initializing K K = '@' # using re.sub() to perform task res = re.sub(r '\@...' , '', test_str) # printing result print ( "The String after removal : " + str (res)) |
The original string is : geeksfor@123geeks is best@212 for cs The String after removal : geeksforgeeks is best for cs
Method #2 : Using re.sub() + occurrence option
This is similar to above, just using 4th argument of re.sub() to control the occurrence counts we wish to perform replace.
Python3
# Python3 code to demonstrate working of # Remove N characters after K # Using re.sub() + occurrence option import re # initializing strings test_str = 'geeksfor@123geeks is best@212 for cs' # printing original string print ( "The original string is : " + str (test_str)) # initializing N N = 3 # initializing K K = '@' # using re.sub() to perform task # controlling occurrence using 4th arg. # removes just 1st occurrence res = re.sub(r '\@...' , '', test_str, 1 ) # printing result print ( "The String after removal : " + str (res)) |
The original string is : geeksfor@123geeks is best@212 for cs The String after removal : geeksforgeeks is best@212 for cs
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