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Python | Relative sorted order in Matrix

  • Last Updated : 11 May, 2020

Sometimes, while working with Python Matrix, we can have data arranged randomly and we can have a requirement in which we need to get the element position in sorted order of Matrix. Let’s discuss a certain way in which this task can be performed.

Method : Using list comprehension + enumerate() + sort() + lambda
The solution to problem can be achieved using the combination of above functions. In these, we need to first arrange element for index value tuple creation using enumerate() and list comprehension. Then, we employ sort function to perform custom sort using lambda function.

Code :




# Python3 code to demonstrate working of
# Relative sorted order in Matrix
# using list comprehension + enumerate() + sort() + lambda
  
# initialize list
test_list = [[1, 3, 1], [4, 6], [7, 8, 10]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# Relative sorted order in Matrix
# using list comprehension + enumerate() + sort() + lambda
res = [(i, j) for i, x in enumerate(test_list) for
       j, _ in enumerate(x)]
res.sort(key = lambda f: test_list[f[0]][f[1]])
  
# printing result
print("Sorted order of Matrix elements : " + str(res))
Output :
The original list is : [[1, 3, 1], [4, 6], [7, 8, 10]]
Sorted order of Matrix elements : [(0, 0), (0, 2), (0, 1), (1, 0),
                                   (1, 1), (2, 0), (2, 1), (2, 2)]

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