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Python progran to extract rows with common difference elements
  • Last Updated : 12 Nov, 2020

Given a Matrix, extract rows with AP sequence.

Input : test_list = [[4, 7, 10], [8, 10, 12], [10, 11, 13], [6, 8, 10]] 
Output : [[4, 7, 10], [8, 10, 12], [6, 8, 10]] 
Explanation : 3, 4, and 2 are common difference in AP.

Input : test_list = [[4, 7, 10], [8, 10, 13], [10, 11, 13], [6, 8, 10]] 
Output : [[4, 7, 10], [6, 8, 10]] 
Explanation : 3 and 2 are common difference in AP. 

Method #1: Using loop 

In this, we check for all the elements having a common difference using a loop, if any element not found to be in sync, then the row is flagged off and not added to the result.



Python3




# Python3 code to demonstrate working of 
# Extract rows with common difference elements
# Using loop
  
# initializing list
test_list = [[4, 7, 10],
             [8, 10, 12],
             [10, 11, 13], 
             [6, 8, 10]]
  
# printing original list
print("The original list is : " + str(test_list))
          
res = []
for row in test_list:
    flag = True 
    for idx in range(0, len(row) - 1):
          
        # check for common difference
        if row[idx + 1] - row[idx] != row[1] - row[0]:
            flag = False 
            break
    if flag :
        res.append(row)
  
# printing result 
print("Filtered Matrix : " + str(res))

Output:

The original list is : [[4, 7, 10], [8, 10, 12], [10, 11, 13], [6, 8, 10]]
Filtered Matrix : [[4, 7, 10], [8, 10, 12], [6, 8, 10]]

Method #2: Using all() + list comprehension

In this, we check for all values to have common difference using all(), list comprehension is used to perform an iteration of rows.

Python3




# Python3 code to demonstrate working of 
# all() + list comprehension
# Using list comprehension + all()
  
# initializing list
test_list = [[4, 7, 10],
             [8, 10, 12],
             [10, 11, 13], 
             [6, 8, 10]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# checking for all values to have common difference         
res = [row for row in test_list
       if all(row[idx + 1] - row[idx] == row[1] - row[0]
              for idx in range(0, len(row) - 1))]
  
# printing result 
print("Filtered Matrix : " + str(res))

Output:

The original list is : [[4, 7, 10], [8, 10, 12], [10, 11, 13], [6, 8, 10]]
Filtered Matrix : [[4, 7, 10], [8, 10, 12], [6, 8, 10]]

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