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Python Program to Remove Nth element from Kth key’s value from the dictionary
• Last Updated : 02 Feb, 2021

Given a dictionary with value lists, our task is to write a Python program to remove N element from Kth key’s values.

Examples:

Input : test_dict = {“gfg” : [9, 4, 5, 2, 3, 2], “is” : [1, 2, 3, 4, 3, 2], “best” : [2, 2, 2, 3, 4]}, K, N = “gfg”, 2

Output : {‘gfg’: [9, 4, 5, 3], ‘is’: [1, 2, 3, 4, 3, 2], ‘best’: [2, 2, 2, 3, 4]}

Explanation : 2 removed from “gfg” key’s value list.

Input : test_dict = {“gfg” : [9, 4, 5, 2, 3, 2], “is” : [1, 2, 3, 4, 3, 2], “best” : [2, 2, 2, 3, 4]}, K, N = “gfg”, 4

Output : {‘gfg’: [9, 5, 2, 3, 2], ‘is’: [1, 2, 3, 4, 3, 2], ‘best’: [2, 2, 2, 3, 4]}

Explanation : 4 removed from “gfg” key’s value list.

Method #1 : Using loop + conditional statements

In this, reassignment of all the key along with their values is done, when K key occurs, N’s occurrence from its value list is omitted.

## Python3

 # Python3 code to demonstrate working of# Remove N from K key's value in dictionary values list# Using loop + conditional statements  # initializing dictionarytest_dict = {"gfg" : [9, 4, 5, 2, 3, 2],             "is" : [1, 2, 3, 4, 3, 2],             "best" : [2, 2, 2, 3, 4]}  # printing original dictionaryprint("The original dictionary is : " + str(test_dict))  # initializing K, N K, N = "gfg", 2  res = dict()for key, val in test_dict.items():          # reassigning omitting desired number    res[key] = (val if key != K else [idx for idx in val if idx != N])  # printing resultprint("The altered dictionary : " + str(res))

Output:

The original dictionary is : {‘gfg’: [9, 4, 5, 2, 3, 2], ‘is’: [1, 2, 3, 4, 3, 2], ‘best’: [2, 2, 2, 3, 4]}

The altered dictionary : {‘gfg’: [9, 4, 5, 3], ‘is’: [1, 2, 3, 4, 3, 2], ‘best’: [2, 2, 2, 3, 4]}

Method #2 : Using dictionary comprehension

In this, we perform similar task to above method, difference being use of dictionary comprehension instead of looping through keys using conventional loop.

## Python3

 # Python3 code to demonstrate working of# Remove N from K key's value in dictionary values list# Using dictionary comprehension  # initializing dictionarytest_dict = {"gfg" : [9, 4, 5, 2, 3, 2],             "is" : [1, 2, 3, 4, 3, 2],              "best" : [2, 2, 2, 3, 4]}  # printing original dictionaryprint("The original dictionary is : " + str(test_dict))  # initializing K, N K, N = "gfg", 2  # dictionary comprehension used for shorthandres = {key : (val if key != K else [idx for idx in val if idx != N]) for key, val in test_dict.items()}  # printing resultprint("The altered dictionary : " + str(res))

Output:

The original dictionary is : {‘gfg’: [9, 4, 5, 2, 3, 2], ‘is’: [1, 2, 3, 4, 3, 2], ‘best’: [2, 2, 2, 3, 4]}

The altered dictionary : {‘gfg’: [9, 4, 5, 3], ‘is’: [1, 2, 3, 4, 3, 2], ‘best’: [2, 2, 2, 3, 4]}

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