Python – Remove Kth key from dictionary

Many times, while working with Python, we can have a situation in which we require to remove the Kth key of the dictionary. This is useful for Python version 3.8 +, where key ordering is similar to the insertion order. Let’s discuss certain ways in which this task can be performed.

Examples:

Input : test_dict = {“Gfg” : 20, “is” : 36, “best” : 100, “for” : 17, “geeks” : 1} , K = 4 
Output : {‘Gfg’: 20, ‘is’: 36, ‘best’ : 100, ‘geeks’: 1} 
Explanation : 4th index, for is removed.

Input : test_dict = {“Gfg” : 20, “is” : 36, “best” : 100, “for” : 17, “geeks” : 1} , K = 2 
Output : {‘Gfg’: 20, ‘best’ : 100, ‘for’ : 17, ‘geeks’: 1} 
Explanation : 2nd index, ‘is’ is removed. 

Method #1 : Using del + loop



This is one of the ways in which this task can be performed. In this, we iterate for the keys, along with the counter, when we get the key, we perform its removal. This performs inplace removal.

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# Python3 code to demonstrate working of 
# Remove Kth key from dictionary
# Using loop
  
# initializing dictionary
test_dict = {"Gfg" : 20, "is" : 36, "best" : 100,
             "for" : 17, "geeks" : 1
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# initializing size 
K = 3
  
cnt = 0
for key in test_dict:
    cnt += 1
      
    # delete key if counter is equal to K
    if cnt == K:
        del test_dict[key]
        break
      
# printing result 
print("Required dictionary after removal : " + str(test_dict)) 

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Output:

The original dictionary is : {‘Gfg’: 20, ‘is’: 36, ‘best’: 100, ‘for’: 17, ‘geeks’: 1}
Required dictionary after removal : {‘Gfg’: 20, ‘is’: 36, ‘for’: 17, ‘geeks’: 1}

Method #2 : Using keys() + dictionary comprehension

This is yet another way in which this task can be performed. In this, we recreate the dictionary without including the required key, by extracting key to be removed using keys(), we include all keys except required into new dictionary.

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# Python3 code to demonstrate working of 
# Remove Kth key from dictionary
# Using Remove Kth key from dictionary
  
# initializing dictionary
test_dict = {"Gfg" : 20, "is" : 36, "best" : 100,
             "for" : 17, "geeks" : 1
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# initializing size 
K = 3
  
# dictionary comprehension remakes dictionary, 
# rather than removing
res = {key: val for key, val in test_dict.items() 
       if key != list(test_dict.keys())[K - 1]}
      
# printing result 
print("Required dictionary after removal : " + str(res))

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Output:

The original dictionary is : {‘Gfg’: 20, ‘is’: 36, ‘best’: 100, ‘for’: 17, ‘geeks’: 1}
Required dictionary after removal : {‘Gfg’: 20, ‘is’: 36, ‘for’: 17, ‘geeks’: 1}

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