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# Python program to find the character position of Kth word from a list of strings

• Difficulty Level : Medium
• Last Updated : 24 Aug, 2022

Given a list of strings. The task is to find the index of the character position for the word, which lies at the Kth index in the list of strings.

Examples:

Input : test_list = [“geekforgeeks”, “is”, “best”, “for”, “geeks”], K = 21
Output : 0
Explanation : 21st index occurs in “geeks” and point to “g” which is 0th element of word.

Input : test_list = [“geekforgeeks”, “is”, “best”, “for”, “geeks”], K = 15
Output : 1
Explanation : 15th index occurs in “best” and point to “e” which is 1st element of word.

Method #1 : Using enumerate() + list comprehension

In this, we use nested enumerate() to check indices for words, and strings in the list, list comprehension is used to encapsulate logic in 1 liner.

## Python3

 `# Python3 code to demonstrate working of``# Word Index for K position in Strings List``# Using enumerate() + list comprehension` `# initializing list``test_list ``=` `[``"geekforgeeks"``, ``"is"``, ``"best"``, ``"for"``, ``"geeks"``]` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))` `# initializing K``K ``=` `20` `# enumerate to get indices of all inner and outer list``res ``=` `[ele[``0``] ``for` `sub ``in` `enumerate``(test_list) ``for` `ele ``in` `enumerate``(sub[``1``])]` `# getting index of word``res ``=` `res[K]` `# printing result``print``(``"Index of character at Kth position word : "` `+` `str``(res))`

Output

```The original list is : ['geekforgeeks', 'is', 'best', 'for', 'geeks']
Index of character at Kth position word : 2
```

Time Complexity: O(n2)
Auxiliary Space: O(n)

Method #2 : Using next() + zip() + count()

In this, we pair up the number of words with their counts using zip(), and accumulate till we don’t reach Kth Index.

## Python3

 `# Python3 code to demonstrate working of``# Word Index for K position in Strings List``# Using next() + zip() + count()``from` `itertools ``import` `count` `# initializing list``test_list ``=` `[``"geekforgeeks"``, ``"is"``, ``"best"``, ``"for"``, ``"geeks"``]` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))` `# initializing K``K ``=` `20` `# count() for getting count``# pairing using zip()``cnt ``=` `count()``res ``=` `next``(j ``for` `sub ``in` `test_list ``for` `j, idx ``in` `zip``(``    ``range``(``len``(sub)), cnt) ``if` `idx ``=``=` `K)` `# printing result``print``(``"Index of character at Kth position word : "` `+` `str``(res))`

Output

```The original list is : ['geekforgeeks', 'is', 'best', 'for', 'geeks']
Index of character at Kth position word : 2
```

Time Complexity: O(n2)
Auxiliary Space: O(n)

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